7.20 g of NaCl in 500. mL of a NaCl solution
Express your answer with the appropriate units.
The concentration of NaCl in the solution is 7.20 g/500. mL.
To express the concentration of NaCl in the given solution, we need to calculate the molarity (M).
Molarity (M) is defined as the amount of solute (in moles) divided by the volume of the solution (in liters).
First, we need to convert the given mass of NaCl (7.20 g) into moles. The molar mass of NaCl is 58.44 g/mol.
moles of NaCl = mass of NaCl / molar mass of NaCl
= 7.20 g / 58.44 g/mol
Next, we need to convert the given volume of the solution (500. mL) into liters. There are 1000 mL in 1 L.
volume of solution = 500. mL / 1000 mL/L
= 0.500 L
Now we can calculate the molarity:
Molarity (M) = moles of NaCl / volume of solution
= (7.20 g / 58.44 g/mol) / 0.500 L
Solving this equation will give us the molarity of the NaCl solution.
To express the answer with appropriate units, we need to determine the concentration of the sodium chloride (NaCl) solution. The concentration is typically expressed in terms of moles per liter (mol/L) or grams per liter (g/L).
Given:
Mass of NaCl = 7.20 g
Volume of solution = 500. mL
To express the concentration in the appropriate units, we need to convert the volume from milliliters (mL) to liters (L). Since 1 L = 1000 mL, we divide the volume by 1000:
Volume of solution = 500 mL ÷ 1000 = 0.5 L
Now, we can calculate the concentration by dividing the mass of NaCl by the volume of the solution:
Concentration (C) = Mass of NaCl / Volume of solution
C = 7.20 g / 0.5 L
C = 14.4 g/L
Therefore, the concentration of the NaCl solution is 14.4 g/L.