Use the following setup and given equation to find the solution:
1st integer = x
2nd integer = x + 2
3rd integer = x + 4
The sum of the integers is : x + x + 2 + x + 4 = 222
. What is the 2nd integer?
Responses
64
64
74
74
111
111
222
To find the solution, we need to set up and solve the equation that represents the sum of the integers.
The sum of the integers is given by the equation: x + (x + 2) + (x + 4) = 222.
Simplifying the equation: 3x + 6 = 222.
Subtracting 6 from both sides: 3x = 216.
Dividing both sides by 3: x = 72.
Since the 2nd integer is represented by x + 2, we can substitute x = 72 into the expression x + 2 to find the 2nd integer.
2nd integer = 72 + 2 = 74.
Therefore, the 2nd integer is 74.
To find the solution, we need to set up an equation using the given information.
1st integer: x
2nd integer: x + 2
3rd integer: x + 4
The sum of the integers is given as x + x + 2 + x + 4 = 222.
Now, let's solve the equation step-by-step:
Combine like terms: 3x + 6 = 222
Subtract 6 from both sides: 3x = 216
Divide both sides by 3: x = 72
Now that we know the value of x, we can find the 2nd integer:
2nd integer = x + 2 = 72 + 2 = 74
Therefore, the 2nd integer is 74.
To find the solution, we need to solve the equation x + (x + 2) + (x + 4) = 222.
To do this, we can combine the like terms on the left side of the equation:
3x + 6 = 222
Next, we can isolate x by subtracting 6 from both sides of the equation:
3x = 216
Then, we can solve for x by dividing both sides of the equation by 3:
x = 72
Now that we have found the value of x, we can find the second integer by adding 2 to x:
x + 2 = 72 + 2 = 74
Therefore, the second integer is 74.