Solve the following equation algebraically. Show your work. 6=x+2/3
(x+2/3) is a fraction
To solve the equation, we need to isolate the variable x.
We start by subtracting 2/3 from both sides:
6 - 2/3 = x + 2/3 - 2/3
Simplifying the left side:
(18/3) - (2/3) = x
Now add and subtract the fractions:
(18 - 2) / 3 = x
Simplifying the numerator:
16 / 3 = x
Therefore, the solution to the equation is x = 16/3.
To solve the equation algebraically, we want to isolate the variable x on one side of the equation.
Given: 6 = x + 2/3
To isolate the x variable, we need to get rid of the fraction on the right side.
We can do this by subtracting 2/3 from both sides of the equation:
6 - 2/3 = x + 2/3 - 2/3
On the left side, 6 can be expressed as a fraction by multiplying both the numerator and the denominator by 3:
(6 * 3)/3 - 2/3 = x
18/3 - 2/3 = x
16/3 = x
So, the solution to the equation is x = 16/3.
To solve the equation 6 = x + 2/3 algebraically, we need to isolate the variable x. Here's how we can do it:
Step 1: Subtract 2/3 from both sides of the equation to move the constant term to the other side.
6 - 2/3 = x + 2/3 - 2/3
Simplifying the equation, we have:
18/3 - 2/3 = x + 0
Which reduces to:
16/3 = x
So, the value of x that satisfies the equation is x = 16/3.