two eighth grade classes are selling snacks to raise money for decorations.
one class is selling snacks for $2.50 each and has already raised $150
the other class is selling snacks for $2.00 each and has already raised $200
Which equation can be used to find x, the number of snacks each class needs to sell so that the total amount raised is the same for both classes?
a 2.5x + 200 = 2x +150
b 2x + 200 = 2.5x + 150
c 2 + 200x + 2.5 + 150x
d 2x + 200x = 2.5x + 150
The equation that can be used to find x, the number of snacks each class needs to sell so that the total amount raised is the same for both classes is:
b) 2x + 200 = 2.5x + 150
The equation that can be used to find x, the number of snacks each class needs to sell so that the total amount raised is the same for both classes is:
b) 2x + 200 = 2.5x + 150.
To answer the question, we need to compare the total amount each class has raised and find the equation that represents this situation.
Let's start with the first class. They are selling snacks for $2.50 each and have already raised $150. To find the total amount they have raised, we multiply the number of snacks they have sold (let's call it x) by the price per snack ($2.50). So, the total amount they have raised can be represented as 2.50x.
Now let's move on to the second class. They are selling snacks for $2.00 each and have already raised $200. Following the same logic, the total amount they have raised can be represented as 2.00x.
Since we want to find the number of snacks each class needs to sell so that the total amount raised is the same for both classes, we can set the two expressions equal to each other.
The equation becomes: 2.50x = 2.00x + 150 (since the first class has raised $150 less than the second class)
Rearranging the equation to have the variables on one side, we get: 2.50x - 2.00x = 150, which simplifies to 0.50x = 150.
Therefore, the correct equation is: 0.50x = 150, which can be rewritten as b) 2x + 200 = 2.5x + 150.