What is the final volume, in liters, of this gas given to a patient at a pressure of 1.0 atm with no change in temperature and amount of gas? Express your answer using two significant figures

Without knowing the initial volume of the gas, it is not possible to determine the final volume. The information provided only states the initial pressure, with no change in temperature and amount of gas. The ideal gas law (PV = nRT) cannot be used to calculate the final volume without one additional piece of information.

To determine the final volume of the gas, we need to know the initial volume of the gas and how the gas is compressed or expanded. Since there is no information provided about the initial volume or the process of compression or expansion, it is not possible to calculate the final volume of the gas.

To find the final volume of the gas, we can use the ideal gas law:

PV = nRT

Where:
- P is the pressure of the gas
- V is the volume of the gas
- n is the amount of gas (which remains constant)
- R is the ideal gas constant
- T is the temperature (which remains constant)

In this case, we are given:
- P = 1.0 atm (atmospheres)
- n and T remain constant

Since we want to express the answer using two significant figures, we will round the final result to two decimal places.

To calculate the final volume, we need the ideal gas constant, R. The value of R depends on the units used for pressure, volume, and temperature. In this case, we need to use the value of R with pressure in atmospheres (atm), volume in liters (L), and temperature in Kelvin (K). The value of R in these units is approximately 0.0821 L·atm/(mol·K).

Using the ideal gas law equation, we can rearrange it to solve for V:

V = (nRT) / P

Substituting the given values, we have:

V = (n * 1.0 atm * R) / P

Since n and R are constants, we can simplify the equation:

V = (constant) / P

Now we can substitute the values and calculate the final volume. However, without additional information about the amount of gas (n), we cannot provide an exact numerical answer.