A candy store makes an 8-pound mixture of gummy candy (g), jelly beans (j), and hard candy (h). The cost of gummy candy is $2.00 per pound, jelly beans cost $3.00 per pound, and hard candy costs $3.00 per pound. The mixture calls for four times as many gummy candy pieces as jelly beans. The total cost of the mixture is $20.00. Question 1 Which system of equations could be used to answer the question, "How many lbs of each ingredient did the store use?" (1 point) Responses 2g+3j+3h=8 2g+3j+3h=20 2 g plus 3 j plus 3 h is equal to 8 2 g plus 3 j plus 3 h is equal to 20 g+j+h=20 2g+3j+3h=8 4g=j g plus j plus h is equal to 20 2 g plus 3 j plus 3 h is equal to 8 4 g is equal to j 2g+3j+3h=28 g=4j 2 g plus 3 j plus 3 h is equal to 28 g is equal to 4 j g+j+h=8 2g+3j+3h=20 g=4j

Question

A candy store makes an 8-pound mixture of gummy candy (g), jelly beans (j), and hard candy (h). The cost of gummy candy is $2.00 per pound, jelly beans cost $3.00 per pound, and hard candy costs $3.00 per pound. The mixture calls for four times as many gummy candy pieces as jelly beans. The total cost of the mixture is $20.00. Question 1 Which system of equations could be used to answer the question, "How many lbs of each ingredient did the store use?" (1 point) Responses 2g+3j+3h=8 2g+3j+3h=20 2 g plus 3 j plus 3 h is equal to 8 2 g plus 3 j plus 3 h is equal to 20 g+j+h=20 2g+3j+3h=8 4g=j g plus j plus h is equal to 20 2 g plus 3 j plus 3 h is equal to 8 4 g is equal to j 2g+3j+3h=28 g=4j 2 g plus 3 j plus 3 h is equal to 28 g is equal to 4 j g+j+h=8 2g+3j+3h=20 g=4j

Answer 1

The correct system of equations that could be used to answer the question, "How many lbs of each ingredient did the store use?" is:

g + j + h = 8

2g + 3j + 3h = 20

Answer 2

The system of equations that could be used to answer the question, "How many lbs of each ingredient did the store use?" is:

g + j + h = 8
2g + 3j + 3h = 20
4g = j

Answer 3

The correct system of equations would be:

1. g + j + h = 8 (Equation representing the total weight of the mixture)
2. 2g + 3j + 3h = 20 (Equation representing the total cost of the mixture)

Explanation:
To determine how many pounds of each ingredient were used in the mixture, we need to set up a system of equations. Let's define the variables:

- g: Number of pounds of gummy candy
- j: Number of pounds of jelly beans
- h: Number of pounds of hard candy

The first equation represents the total weight of the mixture, which is given as 8 pounds. So, the sum of the pounds of gummy candy, jelly beans, and hard candy should be equal to 8, hence g + j + h = 8.

The second equation represents the total cost of the mixture, which is given as $20. The cost of gummy candy is $2.00 per pound, jelly beans cost $3.00 per pound, and hard candy also costs $3.00 per pound. So, we multiply the number of pounds of each ingredient by their respective costs, and the sum of these products should be equal to $20. Hence, 2g + 3j + 3h = 20.

Therefore, the system of equations that could be used to answer the question, "How many pounds of each ingredient did the store use?" is g + j + h = 8 and 2g + 3j + 3h = 20. The correct answer choice is "g+j+h=8" and "2g+3j+3h=20".