The sophomore class sold a total of 700 adult and student tickets to the school play. Adult tickets sold for $4.50 each, and student tickets cost $2.00 each. If they took in a total of $1,200, which system of equations can be used to find x, the number of student tickets sold, and y, the number of adult tickets sold?(1 point) Responses {2x+4.5y=12002x−4.5y=700
The correct system of equations would be:
x + y = 700 (since the total number of tickets sold is 700)
2x + 4.5y = 1200 (since the total ticket sales add up to $1200)
The correct system of equations to find x and y, the number of student and adult tickets sold respectively, is:
2x + 4.5y = 1200
x + y = 700
The first equation represents the total revenue from student and adult tickets, while the second equation represents the total number of tickets sold.
To set up a system of equations to solve for the number of student tickets sold (x) and the number of adult tickets sold (y), we need to consider the given information.
We know that the total number of tickets sold is 700. Therefore, the sum of the number of student tickets (x) and the number of adult tickets (y) must equal 700:
x + y = 700
Next, we know that the revenue from the ticket sales is $1,200. The number of student tickets (x) sold at $2.00 each and the number of adult tickets (y) sold at $4.50 each will give us the total revenue. So we can set up the equation:
2x + 4.5y = 1200
Therefore, the correct system of equations for finding x and y is:
x + y = 700
2x + 4.5y = 1200