A public aquarium is being built to contain neon tetras. Each neon tetra needs 1.25 gallons of water. The aquarium will contain 1×10^5 gallons of water. How many tetras can it house? Write the answer in scientific notation.
To find the number of tetras that can be housed in the aquarium, we need to divide the total volume of water in the aquarium by the volume of water needed for each neon tetra.
Number of tetras = Total volume of water / Volume of water needed for each tetra
Number of tetras = (1×10^5 gallons) / (1.25 gallons/tetra)
Number of tetras = 8 × 10^4
Therefore, the aquarium can house 8 × 10^4 neon tetras.
To find out how many neon tetras can be housed in the aquarium, divide the total volume of water in the aquarium by the amount of water needed per neon tetra.
Volume of water in aquarium = 1 × 10^5 gallons
Water needed per neon tetra = 1.25 gallons
Number of tetras = Volume of water in aquarium / Water needed per neon tetra
Number of tetras = (1 × 10^5 gallons) / (1.25 gallons)
To divide the numbers, subtract the exponents of 10: 10^5 / 10^0 = 10^(5-0) = 10^5
Number of tetras = 10^5 / 1.25
Divide the coefficients: 10^5 divided by 1.25 equals 80,000
Therefore, the aquarium can house 80,000 neon tetras. The answer in scientific notation is 8 × 10^4.
To find out how many neon tetras the aquarium can house, we need to divide the total gallons of water in the aquarium by the amount of water each tetra needs.
Total gallons of water in the aquarium = 1 × 10^5 gallons
Gallons of water needed per tetra = 1.25 gallons
So, the number of tetras that can be housed is given by:
Number of tetras = Total gallons of water in the aquarium / Gallons of water needed per tetra
Number of tetras = (1 × 10^5 gallons) / (1.25 gallons)
To divide these numbers, we can divide the coefficients and subtract the exponents:
Number of tetras = 8 × 10^4 tetras
Therefore, the public aquarium can house 8 × 10^4 (or 80,000) neon tetras.