Claire works two jobs; she works 54 hours in one week with these two jobs and makes $10 an hour. She is trying to save up for a trip that cost her $5000. She has set aside $1500 already. Write an inequality to represent the minimum amount of weeks she needs to work to save at least 5000. (1 point)
Responses
54(10)x+1500≥5000
54 10 x plus 1500 is greater than or equal to 5000
10x+1500≥5000
10 x plus 1500 is greater than or equal to 5000
54(10)x−1500≤5000
54 10 x minus 1500 is less than or equal to 5000
10x+1500≤5000
10x + 1500 ≤ 5000
10x + 1500 ≤ 5000
The correct inequality to represent the minimum amount of weeks Claire needs to work in order to save at least $5000 is:
10x + 1500 ≥ 5000
Explanation:
To solve this problem, we need to consider that Claire works 54 hours in one week, and she earns $10 per hour. So, in one week, she earns 54 * $10 = $540.
She already has $1500 set aside, so we can add that to her earnings in one week to calculate the total amount she can save in one week: $540 + $1500 = $2040.
Now, we want to find the minimum number of weeks (represented by 'x') that Claire needs to work in order to save at least $5000. So, we multiply the total amount she can save in one week, $2040, by the number of weeks, 'x', and set it equal to or greater than $5000.
Therefore, the inequality that represents this situation is: 10x + 1500 ≥ 5000.