The Moment of Impact Quick Check 2 of 52 of 5 Items Question In a closed system, a ball with a mass of 3 kg and a momentum of 24 kg·m/s collides into a ball with a mass of 1 kg that is originally at rest. Which statement describes the momentum of the balls and the total momentum?(1 point) Responses The momentum of each ball changes, and the total momentum changes. The momentum of each ball changes, and the total momentum changes. The momentum of each ball stays the same, and the total momentum changes. The momentum of each ball stays the same, and the total momentum changes. The momentum of each ball stays the same, and the total momentum stays the same. The momentum of each ball stays the same, and the total momentum stays the same. The momentum of each ball changes, and the total momentum stays the same.
The momentum of each ball changes, and the total momentum stays the same.
In a closed system, three objects have the following momentums: 110 kg⋅m/s , −65 kg⋅m/s , and −100 kg⋅m/s . The objects collide and move together. What is the total momentum after the collision?(1 point) Responses −275 kg⋅m/s negative 275 kilograms times meters per second −55 kg⋅m/s negative 55 kilograms times meters per second 275 kg⋅m/s 275 kilograms times meters per second 55 kg⋅m/s
To find the total momentum after the collision, we need to add up the momentums of all three objects.
110 kg⋅m/s + (-65 kg⋅m/s) + (-100 kg⋅m/s) = -55 kg⋅m/s
Therefore, the total momentum after the collision is -55 kg⋅m/s.
In a closed system, an object with a mass of 1.5 kg collides with a second object. The two objects then move together at a velocity of 50 m/s . The total momentum of the system is 250 kg⋅m/s . What is the mass of the second object? (1 point) Responses 3.5 kg 3.5 kg 3.0 kg 3.0 kg 5.0 kg 5.0 kg 1.5 kg
To find the mass of the second object, we can use the equation for momentum:
Total momentum = mass of first object * velocity of first object + mass of second object * velocity of second object.
250 kg⋅m/s = 1.5 kg * 0 m/s + mass of second object * 50 m/s
250 kg⋅m/s = 50 m/s * mass of second object
Dividing both sides of the equation by 50 kg⋅m/s:
5 = mass of second object
Therefore, the mass of the second object is 5 kg.
A cue stick has a mass of 0.5 kg. The cue stick hits a ball with a mass of 0.2 kg at a velocity of 2.5 m/s. What is the velocity of the ball after it is hit? (1 point) Responses 3.6 m/s 3.6 m/s 8.3 m/s 8.3 m/s 6.3 m/s 6.3 m/s 2.5 m/s
To find the velocity of the ball after it is hit, we can use the law of conservation of momentum.
The initial momentum of the system before the collision is equal to the final momentum of the system after the collision.
Initial momentum = Final momentum
(mass of cue stick * initial velocity of cue stick) + (mass of ball * initial velocity of ball) = (mass of cue stick * final velocity of cue stick) + (mass of ball * final velocity of ball)
(0.5 kg * 2.5 m/s) + (0.2 kg * 0 m/s) = (0.5 kg * final velocity of cue stick) + (0.2 kg * final velocity of ball)
1.25 kg⋅m/s = 0.5 kg * final velocity of cue stick + 0.2 kg * final velocity of ball
Since the ball is at rest initially (0 m/s), the term (0.2 kg * 0 m/s) will be 0, and we can simplify the equation to:
1.25 kg⋅m/s = 0.5 kg * final velocity of cue stick
Dividing both sides of the equation by 0.5 kg:
final velocity of cue stick = 1.25 kg⋅m/s / 0.5 kg
final velocity of cue stick = 2.5 m/s
Therefore, the velocity of the ball after it is hit is 2.5 m/s.