A dihybrid cross displays the possible allele combinations for two different traits. In pea plants, seed can be yellow (dominant) or green (recessive). They can also have a smooth seed texture (dominant) or wrinkled (recessive). Using the diagram below, identify the probability (as a percentage) of offspring with GREEN SEEDS AND SMOOTH TEXTURE.
*
1 point1/16 (6.25%)
8/16 (50%)
3/16 (18.75%)
4/16 (25%)
Based on the diagram below, the probability of offspring with green seeds and smooth texture is 1/16 , which is equivalent to 6.25%.
Diagram:
Y = Yellow seed (dominant)
y = Green seed (recessive)
S = Smooth texture (dominant)
s = Wrinkled texture (recessive)
Punnett Square:
| YS | Ys | yS | ys |
_____|_____|_____|_____|_____|
YS | YSYS | YsS | YsS | YsS |
_____|_____|_____|_____|_____|
Ys | YSYS | YsS | ySs | ysS |
_____|_____|_____|_____|_____|
yS | YsS | ysS | ySs | ysS |
_____|_____|_____|_____|_____|
ys | YsS | ysS | ysS | yss |
_____|_____|_____|_____|_____|
Out of the 16 possible allele combinations, there is only one combination that results in offspring with green seeds and smooth texture (ysS). Therefore, the probability is 1/16 or 6.25%.
So, the correct answer is:
1 point1/16 (6.25%)
To solve this problem, we can use the Punnett square method. Let's set up a Punnett square to determine the possible allele combinations:
Y y
S YS Ys
s YS Ys
In this case, Y represents the yellow seed allele (dominant) and y represents the green seed allele (recessive). Similarly, S represents the smooth texture allele (dominant) and s represents the wrinkled texture allele (recessive).
From the Punnett square, we can see that the only possible genotype that produces offspring with both green seeds and smooth texture is the YsSs combination. This genotype occurs in 1 out of the 16 possible combinations.
Therefore, the probability (as a percentage) of offspring with green seeds and smooth texture is:
1/16 * 100% = 6.25%
So, the correct answer is 1 point: 1/16 (6.25%).
To determine the probability of offspring with green seeds and smooth texture in a dihybrid cross, we need to first understand the different possible allele combinations for the two traits.
In this case, the two traits are seed color and seed texture. Let's represent the dominant allele for yellow seed color as "Y" and the recessive allele for green seed color as "y". Similarly, let's represent the dominant allele for smooth seed texture as "S" and the recessive allele for wrinkled seed texture as "s".
When we perform a dihybrid cross, we need to consider the possible combinations of alleles from each parent. In this case, let's consider one parent to have the genotype "YYSS" and the other parent to have the genotype "yyss". We can represent the gametes produced by each parent as follows:
Parent 1: Gametes = YS
Parent 2: Gametes = ys
To determine the probability of offspring with green seeds and smooth texture, we need to consider the combinations of these gametes. By multiplying the probabilities of each combination, we can find the overall probability.
Possible combinations:
1) YS x ys: This combination would result in offspring with green seeds (yy) and smooth texture (SS). The probability of this combination is (1/2) * (1/2) = 1/4.
2) YS x ys: This combination would also result in offspring with green seeds (yy) and smooth texture (SS). The probability of this combination is (1/2) * (1/2) = 1/4.
3) YS x ys: This combination would result in offspring with green seeds (yy) and smooth texture (Ss). The probability of this combination is (1/2) * (1/2) = 1/4.
4) YS x ys: This combination would result in offspring with green seeds (yy) and smooth texture (Ss). The probability of this combination is (1/2) * (1/2) = 1/4.
Adding up the probabilities of all these combinations, we get:
1/4 + 1/4 + 1/4 + 1/4 = 4/4 = 1.
Therefore, the probability of offspring with green seeds and smooth texture is 100% or 1.
None of the given options (1/16, 8/16, 3/16, 4/16) match the correct answer.