A hockey puck with a mass of 0. 18 kg travels at a velocity of 40 m/s toward a goalkeeper. The goalkeeper mass of 120 kg and is at rest. Assuming a closed system, find the total momentum of the puck before the caught by the goalkeeper. (1 point)
The momentum of an object is given by the formula:
momentum = mass * velocity
Given that the mass of the hockey puck is 0.18 kg and its velocity is 40 m/s, we can calculate its momentum:
momentum of the puck = 0.18 kg * 40 m/s = 7.2 kg*m/s
Since the system is closed, the total momentum before the goalkeeper catches the puck will be equal to the momentum of the puck. Therefore, the total momentum of the system is 7.2 kg*m/s.
The total momentum before the puck is caught by the goalkeeper can be calculated by the formula:
Total momentum = momentum of the puck
Momentum (p) is given by the formula:
Momentum (p) = mass (m) × velocity (v)
Given that the mass of the hockey puck is 0.18 kg and it travels at a velocity of 40 m/s:
Momentum of the puck = 0.18 kg × 40 m/s = 7.2 kg·m/s
Therefore, the total momentum of the puck before it is caught by the goalkeeper is 7.2 kg·m/s.
To find the total momentum of the puck before it is caught by the goalkeeper, we need to use the formula for momentum:
Momentum (p) = mass (m) × velocity (v)
Given that the mass of the puck (m) is 0.18 kg and its velocity (v) is 40 m/s, we can calculate the momentum of the puck.
Momentum of the puck = 0.18 kg × 40 m/s
Momentum of the puck = 7.2 kg·m/s
Therefore, the total momentum of the puck before it is caught by the goalkeeper is 7.2 kg·m/s.