The population of a city is given as 3.45 x 10^6. A nearby city has a population of 1.3 x 10^5 What is the sum of the populations of the two cities in scientific notation? (1 point)
• 3.58 x 10^6
• 35.8 + 10^5
• 4.75 × 10^5
• 4.75 × 10^11
An empty dump truck weighs about 2.8x10^5pounds. How much does it weigh if 15,300 pounds of trash is added? The answer should be in scientific notation. (1 point)
IRSE TOOLS
• 15,302.8 pounds
• 29,530 pounds
• 4.33 x 10^5 pounds
• 2.953 × 10^5 pounds
The half-life of uranium-235 is 700,000,000 years. The half-life of uranium-238 is 4.463 x 10^11 years longer. What is the half-life of uranium-238? The answer should be in decimal form. (1 point)
• 11,463,000,000
• 516,300,000,000
• 4.4637 x 10^11
• 447,000,000,000
The sum of the populations of the two cities can be found by adding the numbers in front of the powers of 10 and keeping the same power of 10.
3.45 x 10^6 + 1.3 x 10^5 = (3.45 + 0.13) x 10^6 = 3.58 x 10^6
Therefore, the sum of the populations of the two cities in scientific notation is 3.58 x 10^6. So, the answer is [3.58 x 10^6].
To find the weight of the dump truck with the added trash, we need to add the weight of the trash to the weight of the empty dump truck.
2.8 × 10^5 pounds + 1.53 × 10^4 pounds = (2.8 + 0.153) × 10^5 pounds = 2.953 × 10^5 pounds
Therefore, the weight of the dump truck with 15,300 pounds of trash added is 2.953 × 10^5 pounds. So, the answer is [2.953 × 10^5 pounds].
To find the half-life of uranium-238, we need to add the additional years to the half-life of uranium-235.
Half-life of uranium-235 = 700,000,000 years
Additional years = 4.463 x 10^11 years
Half-life of uranium-238 = Half-life of uranium-235 + Additional years
= 700,000,000 + 4.463 x 10^11
= 4.463 x 10^11 + 700,000,000
To simplify the expression, we move the decimal point of 700,000,000 to the right by 11 places:
= 4.463 x 10^11 + 0.7 x 10^11
= 5.163 x 10^11
Therefore, the half-life of uranium-238 is 5.163 x 10^11 years. The answer is [516,300,000,000].
To find the total storage of the phone after buying the additional bytes, we need to add the additional bytes to the initial storage.
Initial storage = 1.28 × 10^11 bytes
Additional bytes = 384,000,000,000 bytes
Total storage = Initial storage + Additional bytes
= 1.28 × 10^11 + 384,000,000,000
To simplify the expression, we move the decimal point of 384,000,000,000 to the left by 11 places:
= 1.28 × 10^11 + 3.84 × 10^11
= 5.12 × 10^11
Therefore, the phone would have a total storage of 5.12 × 10^11 bytes. The answer is [5.12 x 10^11].
A mobile phone holds 1.28 x 10^11 bytes of storage. You can also pay more money to get an additional 384,000,000,000 bytes. How much storage would your phone have if you buy the additional bytes? The answer should be in scientific notation. (1 point)
• 385.28 x 10^11
• 385,280,000,000
• 512 × 10^9
• 5.12 x 10^11