The initial conversations of a reactant in zero order is 2.5M. calculate the final concentration of the reactants after 80sec if the rate constants is 0.0034m/s

To calculate the final concentration of the reactants after 80 seconds, we need to use the zero-order rate equation:

[Reactant] = [Initial Concentration] - (Rate Constant * Time)

Given:
Initial concentration = 2.5 M
Rate constant = 0.0034 M/s
Time = 80 s

[Reactant] = 2.5 M - (0.0034 M/s * 80 s)
[Reactant] = 2.5 M - 0.272 M
[Reactant] = 2.228 M

So, the final concentration of the reactant after 80 seconds is approximately 2.228 M.

To calculate the final concentration of the reactant after 80 seconds, we can use the Zero Order Rate Law equation:

[Reactant] = [Reactant]0 - (k * t)

where:
[Reactant] = final concentration of the reactant after time t
[Reactant]0 = initial concentration of the reactant
k = rate constant
t = time

Given:
[Reactant]0 = 2.5 M
k = 0.0034 M/s
t = 80 s

Let's substitute the values into the equation:

[Reactant] = 2.5 M - (0.0034 M/s * 80 s)
[Reactant] = 2.5 M - 0.272 M
[Reactant] = 2.228 M

Therefore, the final concentration of the reactant after 80 seconds is 2.228 M.

To calculate the final concentration of a reactant in zero order, we need to use the zero-order rate equation:

Rate = -k

Where:
Rate is the rate of change in concentration per unit time.
k is the rate constant.

In zero-order reactions, the rate does not depend on the concentration of the reactant. Instead, it depends solely on the value of the rate constant.

Since the rate constant (k) is given as 0.0034 m/s, we can directly use this value to calculate the final concentration of the reactant after a given time.

To find the change in concentration, we multiply the rate constant (k) by the time (t):

Change in concentration = k * t

Given: t = 80 sec

Change in concentration = 0.0034 m/s * 80 sec

Change in concentration = 0.272 M

Now, to find the final concentration, we subtract the change in concentration from the initial concentration:

Final concentration = Initial concentration - Change in concentration

Given: Initial concentration = 2.5 M

Final concentration = 2.5 M - 0.272 M

Final concentration = 2.228 M

Therefore, the final concentration of the reactant after 80 seconds is 2.228 M.