Part one: at the state fair it cost $2.75 for a corn dog and $3.50 for a funnel cake. How much would it cost for you to order C corn dogs and F funnel cakes show how to set this up an algebraic expression.
Part 2: you and your three friends want to order two corn dogs, and one funnel cake, each solve to find out how much it would cost altogether.
Part 3: Explain how you solved part 2
Part one:
To set up an algebraic expression for the cost of ordering C corn dogs and F funnel cakes, we can use the following formula:
Cost = (2.75 * C) + (3.50 * F)
Here, C represents the number of corn dogs ordered, and F represents the number of funnel cakes ordered.
Part two:
To find out how much it would cost for you and your three friends to order two corn dogs and one funnel cake each, we can substitute C = 2 and F = 1 into the algebraic expression set up in part one:
Cost = (2.75 * 2) + (3.50 * 1)
Cost = 5.50 + 3.50
Cost = 9.00
Therefore, it would cost $9.00 altogether for you and your three friends to order two corn dogs and one funnel cake each at the state fair.
Part three:
To solve part two, we substituted the values C = 2 and F = 1 into the algebraic expression we set up in part one. This allows us to calculate the cost by multiplying the price of a corn dog ($2.75) by the number of corn dogs ordered (2), and the price of a funnel cake ($3.50) by the number of funnel cakes ordered (1). Finally, we added these two costs together to find the total cost, which is $9.00.
Part One:
To set up an algebraic expression for the cost of ordering C corn dogs and F funnel cakes, we need to multiply the cost of each item by the number of items ordered and then add them together.
Let's assign variables to represent the number of corn dogs and funnel cakes:
C = number of corn dogs
F = number of funnel cakes
The cost of C corn dogs would be 2.75 * C, and the cost of F funnel cakes would be 3.50 * F. To find the total cost, we add these two expressions together:
Total cost = 2.75 * C + 3.50 * F
This algebraic expression represents the cost of ordering C corn dogs and F funnel cakes.
Part Two:
To find out how much it would cost for you and your three friends to order two corn dogs and one funnel cake each, we substitute the values into the algebraic expression.
Let's assign values to the variables:
C = 2 (two corn dogs)
F = 1 (one funnel cake)
Total cost = 2.75 * 2 + 3.50 * 1
Simplifying,
Total cost = 5.50 + 3.50
Total cost = 9.00
So, it would cost you and your three friends $9.00 in total to order two corn dogs and one funnel cake each.
Part Three:
To solve part two, we plugged in the given values for the number of corn dogs (2) and funnel cakes (1) into the algebraic expression. By substituting these values, we found the cost of two corn dogs (2.75 * 2) and one funnel cake (3.50) individually. Then, we added the costs together to get the total cost of all the items ordered (5.50 + 3.50 = 9.00). Therefore, the total cost for your group would be $9.00.
Part one: To set up an algebraic expression for the cost of ordering C corn dogs and F funnel cakes, you can use the given prices of $2.75 for a corn dog and $3.50 for a funnel cake.
The expression would be:
Cost = (C * $2.75) + (F * $3.50)
Part two: If you and your three friends want to order two corn dogs and one funnel cake each, you need to calculate the total cost.
Using the expression from part one, where C = 2 (two corn dogs) and F = 1 (one funnel cake), we can substitute these values into the expression:
Cost = (2 * $2.75) + (1 * $3.50)
Part three: In part two, we substitute the values for C (2) and F (1) into the expression. By multiplying the quantities of corn dogs and funnel cakes by their respective prices, we can calculate the individual costs.
For the corn dogs: 2 * $2.75 = $5.50
For the funnel cake: 1 * $3.50 = $3.50
Then, we add the individual costs together to find the total cost:
$5.50 + $3.50 = $9.00
Therefore, it would cost a total of $9.00 for you and your three friends to order two corn dogs and one funnel cake each at the state fair.