A group of 45 people attended a ball game. There were twice as many children as adults in the group. Set up a system of equations that represents the numbers of adults and children who attended the game and solve the system to find the number of children who were in the group.

a+c=45 c=2a;15 adults,30 children
a+c=45 a=c+2;30 adults;22 children
a+c=45 c=a+2; 22 adults;30 children
a+c=45 a+2c; 30 adults;15 children

The correct system of equations would be:

a + c = 45
c = 2a

To solve this system, you can substitute the second equation into the first equation:

a + 2a = 45
3a = 45
a = 15

Then, you can substitute the value of a back into the second equation to find the value of c:

c = 2(15)
c = 30

Therefore, there were 30 children in the group.

Let's set up a system of equations to represent the numbers of adults and children who attended the game.

Let a represent the number of adults and c represent the number of children.

We know that there were twice as many children as adults, so we can set up the equation c = 2a.

We also know that the total number of people who attended the game was 45, so we can set up the equation a + c = 45.

Now, we can solve the system of equations to find the number of children who were in the group.

Using the equation c = 2a, we substitute 2a in place of c in the second equation:

a + 2a = 45

Combining like terms, we get:

3a = 45

Dividing both sides by 3, we get:

a = 15

Now, substituting the value of a into the equation c = 2a, we get:

c = 2 * 15

c = 30

Therefore, there were 30 children in the group.

To set up a system of equations representing the number of adults and children in the group, we can use the following information:

1. There were 45 people in total.
2. There were twice as many children as adults.

Let's start by defining our variables. Let a represent the number of adults and c represent the number of children in the group.

From the first piece of information, we can form the equation:
a + c = 45

From the second piece of information, we can form the equation:
c = 2a

Now we have a system of equations:
1. a + c = 45
2. c = 2a

To solve this system, we can substitute equation 2 into equation 1. This means we replace c in equation 1 with 2a:

a + 2a = 45

Combining like terms, we get:
3a = 45

Now we can solve for a by dividing both sides of the equation by 3:
a = 45 / 3
a = 15

Now that we have the value of a, we can substitute it back into equation 2 to find the value of c:
c = 2a
c = 2 * 15
c = 30

Therefore, there were 15 adults and 30 children in the group.