Mr. Brokaw's class has 60 students, 14 of the students needed help for an upcoming test. If Mr. Brokaw equally divides the students that need help into 5 small groups, how many students are in each group
Responses:
15
12
3
5
The correct answer is 3. Mr. Brokaw has 14 students who need help, and he wants to evenly divide them into 5 small groups. If we divide 14 by 5, we get a quotient of 2 with a remainder of 4. This means that each group will have 2 students, and there will be 4 students left over. Since Mr. Brokaw wants to evenly divide the students, he will add those 4 remaining students to each group. Therefore, each small group will have 2 + 4 = 6 students.
Thats wrong..
I apologize for the incorrect response. Let's try to solve the problem again.
Mr. Brokaw has 14 students who need help and he wants to divide them into 5 small groups. To find out how many students are in each group, we divide 14 by 5.
14 ÷ 5 = 2 remainder 4
This means that each group will have 2 students, and there will be 4 students left over. Since Mr. Brokaw wants to evenly divide the students, he will distribute the 4 remaining students across the groups.
Therefore, each small group will have 2 + 1 = 3 students.
So the correct answer is 3. Each small group will have 3 students.
Mr. Brokaw's class has 60 students, 1/4 of the students needed help for an upcoming test. If Mr. Brokaw equally divides the students that need help into 5 small groups, how many students are in each group
15
12
3
5
To find the number of students in each small group, we first need to calculate how many students needed help for the upcoming test.
The total number of students in Mr. Brokaw's class is 60, and 1/4 of the students needed help. To find this number, we multiply 60 by 1/4:
60 * 1/4 = 15
So, 15 students needed help for the upcoming test.
Now, Mr. Brokaw wants to divide these 15 students equally into 5 small groups. To find the number of students in each group, we divide 15 by 5:
15 / 5 = 3
Therefore, there are 3 students in each small group. Thus, the correct answer is 3.
Mr. Brokaw's class has 60 students, 14 of the students needed help for an upcoming test. If Mr. Brokaw equally divides the students that need help into 5 small groups, how many students are in each group
15
12
5
To find the number of students in each small group, we first need to calculate how many students needed help for the upcoming test.
Given that Mr. Brokaw has 14 students who needed help, we need to divide these 14 students into 5 small groups.
When we divide 14 by 5, we get a quotient of 2 with a remainder of 4.
Therefore, each small group will have 2 students, and there will be 4 students left over.
Each of the 5 small groups will have 2 students, and the remaining 4 students do not form a complete group.
So, the correct answer is 2. Each small group will have 2 students.
Mr. Brokaw's class has 60 students, 1/4 of the students needed help for an upcoming test. If Mr. Brokaw equally divides the students that need help into 5 small groups, how many students are in each group
15
12
5
To find the number of students in each small group, we first need to calculate how many students needed help for the upcoming test.
Given that 1/4 of the students needed help, we can calculate this by multiplying the total number of students (60) by 1/4:
60 * 1/4 = 15
So, 15 students needed help for the upcoming test.
Now, Mr. Brokaw wants to divide these 15 students equally into 5 small groups. To find the number of students in each group, we divide 15 by 5:
15 / 5 = 3
Therefore, there will be 3 students in each small group. Thus, the correct answer is 3.
To find the number of students in each group, we need to divide the total number of students who need help by the number of small groups. In this case, there are 14 students who need help and 5 small groups.
To solve this, we can use long division:
____
5 | 14
- 10
----
4
We see that 5 can be divided into 14, 2 times with a remainder of 4. This means that each small group will have 2 students, and there will be a remainder of 4.
Therefore, the correct answer is 2.