Part 1.At the state fair it costs $2.75 for a corn dog and $3.50 for a funnel cake. How much would it cost for you to order “c” corndogs and “f” funnel cakes? Show how to set this up as an algebraic expression.
Part 2. You and your three friends want to order 2 corndogs and 1 funnel cake each. Solve to find out how much it would cost all together.
Part 3 explain how you solved part 2
Part 1: To set up the cost of ordering "c" corn dogs and "f" funnel cakes as an algebraic expression, we can multiply the cost of one corn dog ($2.75) by the number of corn dogs ordered ("c") and multiply the cost of one funnel cake ($3.50) by the number of funnel cakes ordered ("f"). The algebraic expression would be:
Cost = (2.75 * c) + (3.50 * f)
Part 2: To find out how much it would cost altogether for you and your three friends to order 2 corn dogs and 1 funnel cake each, we need to substitute the values into the algebraic expression.
Cost = (2.75 * 2) + (3.50 * 1)
Cost = 5.50 + 3.50
Cost = 9.00
Therefore, it would cost $9.00 altogether for you and your three friends to order 2 corn dogs and 1 funnel cake each.
Part 3: In part 2, I substituted the values of 2 for "c" (the number of corn dogs ordered) and 1 for "f" (the number of funnel cakes ordered) into the algebraic expression. By multiplying the cost of one corn dog ($2.75) by the number of corn dogs ordered (2) and multiplying the cost of one funnel cake ($3.50) by the number of funnel cakes ordered (1), I found the individual costs. Adding up the individual costs, I determined that it would cost $9.00 altogether.
Part 1: To set up an algebraic expression for the cost of ordering "c" corndogs and "f" funnel cakes, we need to multiply the cost of each item by the number of items ordered and then sum them up.
The cost of "c" corndogs would be 2.75c.
The cost of "f" funnel cakes would be 3.50f.
So the algebraic expression for the total cost would be: 2.75c + 3.50f.
Part 2: To find out how much it would cost for you and your three friends to order 2 corndogs and 1 funnel cake each, we substitute the values into the expression from Part 1.
c = 2 (2 corndogs)
f = 1 (1 funnel cake)
The cost would be:
2.75 * 2 + 3.50 * 1 = 5.50 + 3.50 = 9.00
So it would cost a total of $9.00 for you and your three friends to all order 2 corndogs and 1 funnel cake each.
Part 3: In Part 2, I solved the problem by substituting the values of "c" and "f" into the expression from Part 1. By multiplying the cost per item by the number of items ordered and then adding them together, I calculated the total cost.
Part 1: To set up an algebraic expression for the cost of ordering "c" corn dogs and "f" funnel cakes, we can multiply the unit price of each item by the respective quantities and then add the results.
The cost of "c" corn dogs would be 2.75 * c.
The cost of "f" funnel cakes would be 3.50 * f.
Therefore, the algebraic expression for the total cost would be: (2.75 * c) + (3.50 * f).
Part 2: To find out how much it would cost for you and your three friends to order 2 corn dogs and 1 funnel cake each, we need to substitute the given values into the algebraic expression we set up in Part 1.
Let's put c = 2 (since you want to order 2 corn dogs) and f = 1 (since you want to order 1 funnel cake).
Substituting these values into the expression, we have:
(2.75 * 2) + (3.50 * 1)
= 5.50 + 3.50
= 9.00.
Therefore, it would cost $9.00 all together for you and your three friends to order 2 corn dogs and 1 funnel cake each.
Part 3: To solve Part 2, we substituted the given values of c and f into the algebraic expression we set up in Part 1. By doing this, we calculated the cost for each item (corn dogs and funnel cakes) and added them together to find the total cost.