It's a school dance and parents tickets are 4 dollars and students tickets are 2.50 at the end the school made 2820 dollars how many tickets did they sell for parents and students
Let's assume the number of parent tickets sold is P and the number of student tickets sold is S.
According to the given information, the price of each parent ticket is $4, so the total amount collected from parent tickets is 4 * P = 4P dollars.
Similarly, the price of each student ticket is $2.50, so the total amount collected from student tickets is 2.50 * S = 2.5S dollars.
Given that the total amount collected is $2820, we can write an equation:
4P + 2.5S = 2820
Now, we need to find the values of P and S. Since we don't have any other information, it's not possible to determine a unique solution. There are multiple combinations of P and S that satisfy the given equation.
To find the number of tickets sold for parents and students, we can set up an equation based on the given information.
Let's say the number of tickets sold for parents is "P" and the number of tickets sold for students is "S".
The revenue from the parent's tickets can be calculated by multiplying the ticket price ($4) by the number of tickets sold for parents:
Revenue from parents = 4P
Similarly, the revenue from the student's tickets can be calculated by multiplying the ticket price ($2.50) by the number of tickets sold for students:
Revenue from students = 2.50S
Given that the total revenue from ticket sales is $2820, we can set up the equation:
Revenue from parents + Revenue from students = Total revenue
4P + 2.50S = 2820
Now, we need to solve this equation to find the values of P and S.
However, we need additional information to determine the exact values of P and S, as there are multiple solutions possible. Could you please provide any additional information?
To find out how many tickets were sold for parents and students, we can use a system of equations.
Let's say the number of parent tickets sold is represented by 'P', and the number of student tickets sold is represented by 'S'.
From the given information, we can deduce the following equations:
Equation 1: 4P + 2.50S = 2820 (represents the total revenue generated from selling tickets)
Equation 2: P + S = X (represents the total number of tickets sold, where X is an unknown value)
We have two equations and two unknowns, so we can solve this system of equations.
One way to do this is by using substitution. We can rearrange Equation 2 to solve for P:
P = X - S
Substituting this value for P in Equation 1, we get:
4(X - S) + 2.50S = 2820
Expanding the equation gives us:
4X - 4S + 2.50S = 2820
Combining like terms gives us:
4X - 1.50S = 2820
Now, we have one equation with one unknown. We can solve for S:
-1.50S = 2820 - 4X
S = (2820 - 4X) / -1.50
To determine the values of P and S, we need to find two numbers that satisfy both Equation 1 and Equation 2. We can solve this by trial and error, or by setting up a table of possible values for X, and calculating the corresponding values of P and S.
For example, let's try X = 200:
Using the equation:
S = (2820 - 4X) / -1.50
S = (2820 - 4 * 200) / -1.50
S = (2820 - 800) / -1.50
S = 2020 / -1.50
S = -1346.67
Since we cannot have a negative number of tickets sold, we can conclude that X = 200 is not a valid solution. We need to try other values of X until we find a whole number value for S.
Continuing this process of substituting different values of X into the equations will eventually lead to a solution that satisfies both equations.