Suppose that the water level of a river is 45 feet after 3 days of no rain and 10 feet after 10 days of no rain. Given the two points we know: (3, 45) and (10, 10), what would the point slope equation look like?(1 point)
Responses
(y−45)=−5(x−3)
open paren y minus 45 close paren is equal to negative 5 times open paren x minus 3 close paren
(y−10)=−5(x+10)
open paren y minus 10 close paren is equal to negative 5 times open paren x plus 10 close paren
(y−3)=−5(x−45)
open paren y minus 3 close paren is equal to negative 5 times open paren x minus 45 close paren
(y+10)=−5(x−10)
open paren y plus 10 close paren is equal to negative 5 times open paren x minus 10 close paren
open paren y plus 10 close paren is equal to negative 5 times open paren x minus 10 close paren
To find the point-slope equation, we need to use the formula:
(y - y1) = m(x - x1),
where (x1, y1) is one of the given points, and m is the slope of the line.
First, let's find the slope (m) using the two points (3, 45) and (10, 10):
m = (y2 - y1) / (x2 - x1)
= (10 - 45) / (10 - 3)
= -35 / 7
= -5
Now we can plug the values into the point-slope equation using one of the points:
(y - 45) = -5(x - 3)
So the correct answer is:
(y - 45) = -5(x - 3).