An electrical company decides to replace the lightbulbs in all of the nonworking street lights on two specific streets. The company learns that 2/3 of the lights do not work on the first street and 1/6 of the lights do not work on the second street. What is the total fractional portion of the nonworking lights on these two streets?
On the first street, the fraction of nonworking lights is 2/3.
On the second street, the fraction of nonworking lights is 1/6.
To find the total fraction of nonworking lights, we need to add these two fractions.
2/3 + 1/6 = (4/6) + (1/6) = 5/6
Therefore, the total fraction of nonworking lights on these two streets is 5/6. Answer: \boxed{\frac{5}{6}}.
To find the total fractional portion of the nonworking lights on two streets, we need to find the combined fraction of nonworking lights on both streets.
On the first street, 2/3 of the lights do not work.
On the second street, 1/6 of the lights do not work.
To find the combined fraction, we calculate the sum of the fractions:
2/3 + 1/6
We need to find a common denominator for 3 and 6, which is 6.
2/3 is equivalent to (2/3) * (2/2) = 4/6
Now the sum becomes:
4/6 + 1/6
Adding the fractions together, we get:
(4 + 1)/6 = 5/6
So the total fractional portion of the nonworking lights on these two streets is 5/6.
To find the total fractional portion of the nonworking lights on the two streets, we need to add the fractions of nonworking lights on each street.
On the first street, 2/3 of the lights do not work.
On the second street, 1/6 of the lights do not work.
To add fractions, we need a common denominator. In this case, the least common multiple of 3 and 6 is 6.
So, we can write the fractions with a denominator of 6:
For the first street: (2/3) = (4/6) (We multiply the numerator and denominator by 2)
For the second street: (1/6) = (1/6)
Now, we can add the fractions:
(4/6) + (1/6) = (5/6)
Therefore, the total fractional portion of the nonworking lights on these two streets is 5/6.