trapezoid ACFD with A(1, 5), C5, 5), F(4, 4), and D(2, 4) along the translation vector (5, -1). Where is F?
To find the new position of point F after the translation, we need to add the translation vector (5, -1) to the original coordinates of F (4, 4).
Adding the x-coordinates, 4 + 5 = 9.
Adding the y-coordinates, 4 + (-1) = 3.
Therefore, the new coordinates of point F are (9, 3).
To find the new position of point F after the translation, we add the coordinates of the translation vector (5, -1) to the original coordinates of F (4, 4).
So, adding the x-coordinates, we get:
4 + 5 = 9.
Adding the y-coordinates, we get:
4 + (-1) = 3.
Therefore, the new position of point F is (9, 3).
To find the position of point F after a translation along the vector (5, -1), you need to add the corresponding x and y components of the translation vector to the original coordinates of point F.
Given that the translation vector is (5, -1), we can find the new coordinates of point F as follows:
New coordinate of F (x, y) = (Original x coordinate of F + x component of the translation vector, Original y coordinate of F + y component of the translation vector)
Original x coordinate of F = 4
x component of the translation vector = 5
Original y coordinate of F = 4
y component of the translation vector = -1
Plugging in these values:
New x coordinate of F = 4 + 5 = 9
New y coordinate of F = 4 + (-1) = 3
So, after the translation, the new coordinates of point F are (9, 3).
Therefore, point F is located at (9, 3) after the translation.