Let A = \{5, 7, 9\}; B =\ x|x; an even whole number less than 11), C = \{6, 8, 10, 12\} and D=\ x| xi! an odd whole number less than 12). Find AnB.
Select the correct choice and fill in any answer boxes in your choice below.
O. A cap B=\ Box\ (Use a comma to separate answers as needed.)
O B. The solution is the empty set.
AnB = A ∩ B
We know that B consists of even whole numbers less than 11. However, A only contains odd numbers. Therefore, there is no overlap between A and B, and their intersection will be the empty set.
So, the correct choice is:
B. The solution is the empty set.
To find the intersection of sets A and B (A ∩ B), we need to identify the common elements between the two sets.
A = {5, 7, 9} (odd whole numbers)
B = {x | x is an even whole number less than 11}
From set A, we can see that 7 is the only element that satisfies the condition of set B (an even whole number less than 11). Therefore, the intersection of sets A and B is {7}.
So, the correct choice is:
A ∩ B = {7}
To find A ∩ B (the intersection of sets A and B), we need to identify the elements that are common to both sets.
Set A = {5, 7, 9} and set B consists of all even whole numbers less than 11.
The even whole numbers less than 11 are: 2, 4, 6, 8, and 10.
Now we compare the elements of sets A and B:
A ∩ B = {6}
Therefore, the correct choice is: A ∩ B = {6} (Box: 6)