How many grams are in 1.40 moles of dinitrogen oxide?

Express your answer with the appropriate units.

To determine the number of grams in 1.40 moles of dinitrogen oxide, we need to use the molar mass of dinitrogen oxide, which is given by the sum of the atomic masses of each element in one molecule of dinitrogen oxide.

The atomic masses of nitrogen (N) and oxygen (O) are approximately 14.01 g/mol and 16.00 g/mol, respectively.

Therefore, the molar mass of dinitrogen oxide (N2O) is:
(2 × 14.01 g/mol) + 16.00 g/mol = 44.02 g/mol.

To find the number of grams in 1.40 moles of dinitrogen oxide, we can use the following conversion factor:
1.40 moles of N2O × (44.02 g/mol of N2O) = 61.63 g.

Therefore, there are 61.63 grams in 1.40 moles of dinitrogen oxide.

To find the number of grams in 1.40 moles of dinitrogen oxide, you need to know its molar mass. The molar mass of dinitrogen oxide (N2O) can be calculated by adding the atomic masses of nitrogen (N) and oxygen (O).

The atomic mass of nitrogen (N) is approximately 14.01 grams/mole, and the atomic mass of oxygen (O) is approximately 16.00 grams/mole.

So, the molar mass of dinitrogen oxide (N2O) is:

2(N) + 1(O) = (2 * 14.01 g/mole) + (1 * 16.00 g/mole) = 28.02 g/mole + 16.00 g/mole = 44.02 g/mole.

Now, you can use the molar mass to convert moles to grams. Multiply the number of moles (1.40 moles) by the molar mass (44.02 g/mole):

1.40 moles * 44.02 g/mole = 61.63 grams.

Therefore, there are 61.63 grams in 1.40 moles of dinitrogen oxide.

To determine the number of grams in 1.40 moles of dinitrogen oxide, you need to know the molar mass of dinitrogen oxide (N2O).

The molar mass is the mass of one mole of a substance and is expressed in grams per mole (g/mol).

To calculate the molar mass of dinitrogen oxide, you need to consider the atomic masses of nitrogen (N) and oxygen (O) and their respective subscript numbers in the formula N2O.

The atomic mass of nitrogen (N) is approximately 14.01 g/mol, and the atomic mass of oxygen (O) is approximately 16.00 g/mol.

Since there are two nitrogen atoms and one oxygen atom in dinitrogen oxide, you multiply the atomic masses by their respective subscript numbers and sum them up:

(2 x atomic mass of nitrogen) + (1 x atomic mass of oxygen) = (2 x 14.01 g/mol) + (1 x 16.00 g/mol) = 28.02 g/mol + 16.00 g/mol = 44.02 g/mol.

Thus, the molar mass of dinitrogen oxide is approximately 44.02 g/mol.

To find the number of grams in 1.40 moles, you can use the following formula:

Number of grams = Number of moles x Molar mass.

Plugging in the values:

Number of grams = 1.40 moles x 44.02 g/mol = 61.63 grams.

Therefore, there are approximately 61.63 grams in 1.40 moles of dinitrogen oxide.