Find the distance between points (6.16) and Z(-1, 14) to the nearest tenth.
To find the distance between two points, we can use the formula:
distance = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, the coordinates of the first point are (6, 16) and the coordinates of the second point are (-1, 14).
Therefore, the distance between the two points is:
distance = √((-1 - 6)^2 + (14 - 16)^2)
= √((-7)^2 + (-2)^2)
= √(49 + 4)
= √53
≈ 7.3 (nearest tenth)
So, the distance between the points (6, 16) and (-1, 14) is approximately 7.3 units.
To find the distance between two points in a coordinate plane, you can use the distance formula:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
Given the points (6, 16) and (-1, 14), we can assign the values as follows:
x1 = 6
y1 = 16
x2 = -1
y2 = 14
Now we can substitute these values in the distance formula:
Distance = √((-1 - 6)^2 + (14 - 16)^2)
= √((-7)^2 + (-2)^2)
= √(49 + 4)
= √53
Rounding to the nearest tenth, the distance between the points is approximately 7.3.
To find the distance between two points in a coordinate plane, we can use the distance formula. The distance formula is derived from the Pythagorean theorem and is given by:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
In this case, we have two points: (6, 16) and Z(-1, 14). Let's assign the values as follows:
x1 = 6
y1 = 16
x2 = -1
y2 = 14
Now, we can substitute these values into the distance formula:
d = sqrt((-1 - 6)^2 + (14 - 16)^2)
Simplifying further:
d = sqrt((-7)^2 + (-2)^2)
= sqrt(49 + 4)
= sqrt(53)
Therefore, the distance between the given points is approximately √53 or 7.3 units to the nearest tenth.