A cook uses a microwave oven to heat meal. The wavelength is 3.30cm. what is the energy of one photon of this microwave radiation?
To calculate the energy of one photon, we can use the equation:
E = hc/λ,
where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J.s), c is the speed of light (2.998 x 10^8 m/s), and λ is the wavelength of the radiation.
First, we need to convert the wavelength from centimeters to meters:
λ = 3.30 cm = 0.033 m.
Now we can calculate the energy of one photon:
E = (6.626 x 10^-34 J.s * 2.998 x 10^8 m/s) / 0.033 m.
E = 6.022 x 10^-24 J.
Therefore, the energy of one photon of this microwave radiation is approximately 6.022 x 10^-24 Joules.
To calculate the energy of one photon of microwave radiation, we can use the formula:
E = hc / λ
where:
- E is the energy of one photon,
- h is Planck's constant (6.626 x 10^-34 J·s),
- c is the speed of light (3.00 x 10^8 m/s), and
- λ is the wavelength in meters.
First, we need to convert the wavelength from centimeters to meters:
Wavelength in meters (λ) = 3.30 cm ÷ 100 cm/m
= 0.033 m
Now, we can substitute the values into the formula:
E = (6.626 x 10^-34 J·s) × (3.00 x 10^8 m/s) / (0.033 m)
Calculating this equation, we get:
E ≈ 6.01 x 10^-23 J
Therefore, the energy of one photon of microwave radiation with a wavelength of 3.30 cm is approximately 6.01 x 10^-23 Joules.
To find the energy of one photon of microwave radiation, you can use the equation:
E = h * c / λ,
where E represents the energy of one photon, h is Planck's constant (6.626 x 10^-34 J.s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of the radiation.
First, let's convert the given wavelength from centimeters to meters:
3.30 cm = 3.30 x 10^-2 m.
Now we can substitute the values into the equation:
E = (6.626 x 10^-34 J.s) * (3.00 x 10^8 m/s) / (3.30 x 10^-2 m).
Calculating this expression gives us:
E ≈ 5.68 x 10^-24 Joules.
Therefore, the energy of one photon of this microwave radiation is approximately 5.68 x 10^-24 Joules.