It takes one molecule of nitrogen and three molecules of hydrogen to produce two molecules of ammonia, using the following formula
1N2+3H2=2NH3
Which combination of molecules will produce ammonia with no leftovers?
2N2 and 6H2
4N2 and 4H2
5N2 and 6H2
8N2 and 4H2
The correct combination of molecules that will produce ammonia with no leftovers is 4N2 and 4H2.
Using the given formula, 1N2 + 3H2 = 2NH3, we can see that for every two molecules of ammonia produced, we need one molecule of nitrogen (N2) and three molecules of hydrogen (H2).
If we have 4 molecules of nitrogen (4N2) and 4 molecules of hydrogen (4H2), we can multiply the coefficients to calculate the total number of molecules involved:
4N2 + 4H2 = [4(1N2)] + [4(3H2)] = 4N2 + 12H2
Now, we can use the given formula to determine the number of ammonia molecules produced:
= (4N2 + 12H2) / (1N2 + 3H2)
= (4N2 + 12H2) / (1N2 + 3H2)
= (4N2 / 1N2) + (12H2 / 3H2)
= 4 + 4
= 8 ammonia molecules
Therefore, with 4N2 and 4H2, we will produce exactly 8 ammonia molecules with no leftovers.
In the equation
2H2 + 1O2 == 2H2O
If you change the 2H2 to 3H2 molecules and balance, the equation which statement is correct?
It is not possible to produce water without leftover molecules
The equation will produce three molecules of water
The result of the equation will be the same
Each oxygen molecule well, combine with two hydrogen molecules with no leftover molecules
If the equation is changed from 2H2 to 3H2 and balanced, the correct statement is: "Each oxygen molecule will combine with two hydrogen molecules with no leftover molecules."
To balance the equation, we need to ensure that the number of atoms on both sides of the equation is equal. So, for every 2 molecules of H2O on the right-hand side, we have 2 hydrogen atoms and 1 oxygen atom.
If we change the 2H2 to 3H2, we now have 6 hydrogen atoms on the left-hand side. To balance this, we need to have 3 molecules of H2O on the right-hand side. This will give us a total of 6 hydrogen atoms and 3 oxygen atoms, matching the left-hand side.
So, the new balanced equation will be:
3H2 + 1O2 == 3H2O
With this balanced equation, each oxygen molecule will combine with two hydrogen molecules to produce three molecules of water, with no leftover molecules.
In order to determine which combination of molecules will produce ammonia with no leftovers, we need to calculate the total number of molecules for both nitrogen and hydrogen in each combination and then compare it to the required ratio of 1 molecule of nitrogen to 3 molecules of hydrogen to produce 2 molecules of ammonia.
1. For combination (2N2 and 6H2):
- Nitrogen: 2N2 = 2 x 2 = 4 molecules.
- Hydrogen: 6H2 = 6 x 2 = 12 molecules.
Therefore, the ratio of nitrogen to hydrogen is 4:12, which simplifies to 1:3, matching the required ratio. This combination will produce 4/2 = 2 molecules of ammonia.
2. For combination (4N2 and 4H2):
- Nitrogen: 4N2 = 4 x 2 = 8 molecules.
- Hydrogen: 4H2 = 4 x 2 = 8 molecules.
Again, the ratio of nitrogen to hydrogen is 8:8, which simplifies to 1:1. This combination will produce only half the required amount of ammonia (8/2 = 4 molecules), so there will be leftovers.
3. For combination (5N2 and 6H2):
- Nitrogen: 5N2 = 5 x 2 = 10 molecules.
- Hydrogen: 6H2 = 6 x 2 = 12 molecules.
The ratio of nitrogen to hydrogen is 10:12, which does not simplify to the required 1:3 ratio. This combination will not produce the required ammonia ratio, so there will be leftovers.
4. For combination (8N2 and 4H2):
- Nitrogen: 8N2 = 8 x 2 = 16 molecules.
- Hydrogen: 4H2 = 4 x 2 = 8 molecules.
The ratio of nitrogen to hydrogen is 16:8, which simplifies to 2:1. Again, this combination does not match the required ratio, so there will be leftovers.
Therefore, the combination of 2N2 and 6H2 will produce ammonia with no leftovers.
To determine the combination of molecules that will produce ammonia with no leftovers, we need to find the ratio of nitrogen to hydrogen in the balanced equation and then compare it to the given combinations.
The balanced equation shows that for every one molecule of nitrogen, we need three molecules of hydrogen to produce two molecules of ammonia.
Looking at the given combinations:
- Option 1: 2N2 and 6H2
- Option 2: 4N2 and 4H2
- Option 3: 5N2 and 6H2
- Option 4: 8N2 and 4H2
We can calculate the ratio of nitrogen to hydrogen in each option:
- Option 1: (2N2 / 6H2) = 1 / 3
- Option 2: (4N2 / 4H2) = 1 / 1
- Option 3: (5N2 / 6H2) ≈ 5 / 6
- Option 4: (8N2 / 4H2) = 2 / 1
Now, we compare these ratios to the ratio in the balanced equation (1N2 / 3H2):
- Option 1 ratio (1/3) is not equal to the balanced equation ratio (1/3).
- Option 2 ratio (1/1) is equal to the balanced equation ratio (1/3).
- Option 3 ratio (5/6) is not equal to the balanced equation ratio (1/3).
- Option 4 ratio (2/1) is not equal to the balanced equation ratio (1/3).
Therefore, the combination of molecules that will produce ammonia with no leftovers is option 2: 4N2 and 4H2.