(y^?)^2 = y^42
?=
21
To determine the value of ?, we need to isolate it by applying the rules of exponents.
Step 1: Expand the expression on the left side of the equation:
(y^?)^2 = (y^?) × (y^?) = y^(2?)
Step 2: Set the expanded expression equal to y^42:
y^(2?) = y^42
Step 3: Since the bases are the same (y), we can equate the exponents:
2? = 42
Step 4: Divide both sides of the equation by 2 to solve for ?:
2?/2 = 42/2
? = 21
Therefore, the value of ? is 21.
To solve the equation (y^?)^2 = y^42, we need to find the value of "?" that satisfies the equation.
First, we can simplify both sides of the equation by applying the exponent rules:
(y^?)^2 = (y^2)^? = y^(2?)
Now, we have the equation y^(2?) = y^42.
In order for two exponential expressions with the same base (in this case, both are y) to be equal, their exponents must be equal:
2? = 42
To solve this equation for "?", we can divide both sides by 2:
? = 42/2 = 21
Therefore, the solution for "?" in the equation (y^?)^2 = y^42 is ? = 21.