Use the chemical reaction to answer the question.
CaCO3 -- CO2 + CaO
A scientist heats 30 grams of calcium carbonate in the chemical reaction shown.
What is the total mass of the products
To find the total mass of the products, we need to determine the molar masses of each compound involved in the reaction.
The molar mass of calcium carbonate (CaCO3) can be calculated by adding up the atomic masses of each element:
Calcium (Ca): 40.08 g/mol
Carbon (C): 12.01 g/mol
Oxygen (O): 16.00 g/mol (x3 atoms)
Therefore, the molar mass of CaCO3 is:
(40.08 g/mol) + (12.01 g/mol) + (16.00 g/mol x 3) = 100.09 g/mol
In the reaction, 1 mole of calcium carbonate (CaCO3) decomposes to form 1 mole of carbon dioxide (CO2) and 1 mole of calcium oxide (CaO). According to the balanced equation, the molar ratio between calcium carbonate and the products is 1:1:1.
Since the molar mass of CaCO3 is 100.09 g/mol, we can calculate the total mass of the products by multiplying the molar mass by the number of moles of reactant used.
The number of moles of CaCO3 can be calculated using the given mass and molar mass:
moles = mass / molar mass
moles = 30 g / 100.09 g/mol ≈ 0.2999 mol
Since the ratio between CaCO3 and the products is 1:1:1, the number of moles of CO2 and CaO will also be approximately 0.2999 mol each.
To find the total mass of the products, we multiply the moles of each product by their respective molar masses:
Mass of CO2 = moles of CO2 x molar mass of CO2
Mass of CO2 = 0.2999 mol x 44.01 g/mol = 13.20 g
Mass of CaO = moles of CaO x molar mass of CaO
Mass of CaO = 0.2999 mol x 56.08 g/mol = 16.80 g
Therefore, the total mass of the products (CO2 + CaO) is approximately 13.20 g + 16.80 g = 30.00 g.
Note: It is important to note that in a real reaction, the mass might not always be conserved due to factors like reactant impurities, side reactions, or product loss. However, in this theoretical calculation, the mass of the products should theoretically equal the mass of the reactant.
To find the total mass of the products, we need to determine the mass of carbon dioxide (CO2) and calcium oxide (CaO) produced in the reaction.
From the balanced chemical equation:
1 mole of CaCO3 produces 1 mole of CO2 and 1 mole of CaO.
The molar mass of CaCO3 is 100.1 g/mol (40.1 g/mol for calcium + 12.0 g/mol for carbon + 3 * 16.0 g/mol for oxygen).
Given that we have 30 grams of CaCO3, we can use this information to calculate the moles of CaCO3 that react:
30 g CaCO3 * (1 mol CaCO3 / 100.1 g CaCO3) = 0.3 mol CaCO3
Since the mole ratio of CaCO3 to CO2 is 1:1, we will have 0.3 mol of CO2 produced.
The molar mass of CO2 is 44.01 g/mol (12.0 g/mol for carbon + 2 * 16.0 g/mol for oxygen).
Thus, the mass of CO2 produced will be:
0.3 mol CO2 * (44.01 g CO2 / 1 mol CO2) = 13.203 g CO2
Similarly, the mole ratio of CaCO3 to CaO is also 1:1, so we will have 0.3 mol of CaO produced.
The molar mass of CaO is 56.08 g/mol (40.1 g/mol for calcium + 16.0 g/mol for oxygen).
Hence, the mass of CaO produced will be:
0.3 mol CaO * (56.08 g CaO / 1 mol CaO) = 16.824 g CaO
Therefore, the total mass of the products (CO2 + CaO) is:
13.203 g CO2 + 16.824 g CaO = 29.027 g
To find the total mass of the products in the chemical reaction, you will first need to determine the molar masses of carbon dioxide (CO2) and calcium oxide (CaO).
The molar mass of carbon dioxide (CO2) can be calculated by summing the atomic masses of carbon (C) and oxygen (O). The atomic mass of carbon is 12.01 g/mol, and the atomic mass of oxygen is 16.00 g/mol. Therefore, the molar mass of CO2 is:
Molar mass of CO2 = (12.01 g/mol) + (16.00 g/mol) + (16.00 g/mol) = 44.01 g/mol
The molar mass of calcium oxide (CaO) can be calculated similarly. The atomic mass of calcium is 40.08 g/mol, and the atomic mass of oxygen is 16.00 g/mol. Therefore, the molar mass of CaO is:
Molar mass of CaO = (40.08 g/mol) + (16.00 g/mol) = 56.08 g/mol
Now, you can use the balanced chemical equation and the molar masses of the products to find the total mass of the products.
From the equation:
1 mol of CaCO3 produces 1 mol of CO2 and 1 mol of CaO
Since the molar mass of CaCO3 is 100.09 g/mol (40.08 g/mol for calcium + 12.01 g/mol for carbon + 3 * 16.00 g/mol for oxygen), 30 grams of CaCO3 is equal to:
30 g CaCO3 × (1 mol CaCO3 / 100.09 g CaCO3) = 0.2997 mol CaCO3
Since the molar mass of CO2 is 44.01 g/mol, the mass of CO2 produced would be:
0.2997 mol CaCO3 × (1 mol CO2 / 1 mol CaCO3) × (44.01 g CO2 / 1 mol CO2) = 13.18 g CO2
Similarly, since the molar mass of CaO is 56.08 g/mol, the mass of CaO produced would be:
0.2997 mol CaCO3 × (1 mol CaO / 1 mol CaCO3) × (56.08 g CaO / 1 mol CaO) = 16.80 g CaO
Therefore, the total mass of the products (CO2 + CaO) in the chemical reaction is 13.18 g + 16.80 g = 29.98 g.