5. m<AOB = 3x+8 and m<EOD = 2x+48. Solve for x. Then find m<AOB and m<EOD
To solve for x, we can equate the two given expressions for angle measures:
3x + 8 = 2x + 48
Subtracting 2x from both sides gives:
x + 8 = 48
Subtracting 8 from both sides gives:
x = 40
Now that we have solved for x, we can substitute this value back into the original expressions to find the measures of angles AOB and EOD.
m<AOB = 3x + 8 = 3(40) + 8 = 120 + 8 = 128 degrees
m<EOD = 2x + 48 = 2(40) + 48 = 80 + 48 = 128 degrees
Therefore, the measure of angle AOB is 128 degrees and the measure of angle EOD is also 128 degrees.
To solve for x, we need to set the two equations equal to each other and solve for x:
3x + 8 = 2x + 48
Next, we can subtract 2x from both sides of the equation to isolate the variable:
3x - 2x + 8 = 2x - 2x + 48
Simplifying this equation gives:
x + 8 = 48
To isolate x, we can subtract 8 from both sides:
x + 8 - 8 = 48 - 8
This simplifies to:
x = 40
Now, we can substitute the value of x back into the original equations to find the angle measures.
m<AOB = 3x + 8 = 3(40) + 8 = 120 + 8 = 128 degrees
m<EOD = 2x + 48 = 2(40) + 48 = 80 + 48 = 128 degrees
Therefore, m<AOB and m<EOD are both equal to 128 degrees.
To solve for x, we need to set the two given expressions equal to each other and solve for x.
Given:
m<AOB = 3x + 8
m<EOD = 2x + 48
Setting them equal:
3x + 8 = 2x + 48
Now, let's solve for x.
Subtract 2x from both sides:
3x - 2x + 8 = 2x - 2x + 48
x + 8 = 48
Subtract 8 from both sides:
x + 8 - 8 = 48 - 8
x = 40
So, x = 40.
Now, let's find m<AOB and m<EOD using the value of x we just found.
m<AOB = 3x + 8
m<AOB = 3(40) + 8
m<AOB = 120 + 8
m<AOB = 128
m<EOD = 2x + 48
m<EOD = 2(40) + 48
m<EOD = 80 + 48
m<EOD = 128
Thus, m<AOB = 128 and m<EOD = 128.