Asher is 4 Years younger than jacob, and the sum of their ages is 66 find the ages of asher and jacob
Let's assume Asher's age is x.
According to the given information, Jacob's age will then be x+4.
Since the sum of their ages is 66, we can write the equation as:
x + (x+4) = 66
By combining like terms, we get:
2x + 4 = 66
Subtracting 4 from both sides:
2x = 62
Dividing both sides by 2:
x = 31
Therefore, Asher's age is 31 and Jacob's age is 31 + 4 = 35.
Let's use variables to represent the ages of Asher and Jacob. Let's say Asher's age is A and Jacob's age is J.
According to the given information, we have two equations:
1. Asher is 4 years younger than Jacob: A = J - 4
2. The sum of their ages is 66: A + J = 66
Now, we can substitute the value of A from equation 1 into equation 2 to solve for J:
(J - 4) + J = 66
2J - 4 = 66
2J = 70
J = 35
Therefore, Jacob's age is 35.
To find Asher's age, we substitute the value of Jacob's age (35) into equation 1:
A = 35 - 4
A = 31
Hence, Asher's age is 31.
To find the ages of Asher and Jacob, let's set up an equation based on the given information.
Let's assume that Jacob's age is represented by J.
Since Asher is 4 years younger than Jacob, Asher's age is J - 4.
The sum of their ages is 66, so we can express it as an equation:
J + (J - 4) = 66
By simplifying this equation, we get:
2J - 4 = 66
2J = 70
J = 35
Therefore, Jacob is 35 years old.
To find Asher's age, we substitute Jacob's age into the expression we made earlier:
Asher's age = 35 - 4 = 31
So, Asher is 31 years old.