A hamster in a ball begins its journey 5 feet to the left of a refrigerator, travels 20 feet to the right of the refrigerator, and ends its journey directly in front of the refrigerator.%0D%0A%0D%0AIf negative values are assigned to positions to the left of its starting position and positive values are assigned to positions to the right of its starting position, what is the displacement of the hamster?
The hamster starts 5 feet to the left of the refrigerator, meaning its initial position is at -5 feet.
It then travels 20 feet to the right of the refrigerator, so its position changes to -5 + 20 = 15 feet.
Finally, it ends its journey directly in front of the refrigerator, with a position of 0 feet.
Displacement is the change in position from the starting point to the ending point. In this case, the displacement is 0 - (-5) = 0 + 5 = 5 feet.
Therefore, the displacement of the hamster is 5 feet.
A cat wakes up in its bed and visits its food dish to the left of its bed. %0D%0A%0D%0APositions to the right of its bed are assigned a negative value and positions to the left of its bed are assigned a positive value.%0D%0A %0D%0A%0D%0ATime (m)%091%092%093%094%095%0D%0APosition (m)%090%092%094%09-5%09-10%0D%0AWhere did the cat begin and end its journey?
Which statement correctly classifies distance and displacement?
Distance and displacement are both measurements of the distance between two points, but they differ in their categorization:
- Distance is a scalar quantity, meaning it only considers the magnitude or numerical value of the total path traveled, regardless of direction. It is always positive and is measured in units such as meters, kilometers, etc.
- Displacement, on the other hand, is a vector quantity as it considers both the magnitude and direction of the straight-line path between the initial and final positions. It can be positive or negative, depending on the direction, and is measured in the same units as distance.
In summary, the correct statement is that distance is a scalar quantity, whereas displacement is a vector quantity.
On a position vs. time graph, which feature would represent motion in the negative direction over time
On a position vs. time graph, motion in the negative direction over time would be represented by a line or curve that slopes downwards from left to right. This indicates that the position is decreasing as time progresses. The steeper the slope of the line or curve, the faster the motion in the negative direction.
Two construction workers are attempting to pull a slab of concrete off of the ground. Each of the workers are pulling up with a force of 225 N, while the slab of concrete applies a gravitational force of 400 N in the opposite direction, remaining stationary. If the pulling forces applied to the slab of concrete are assigned a positive value, what is the net force of the scenario, and in which direction will the slab of concrete move?
To determine the net force, we need to calculate the vector sum of all the forces acting on the slab of concrete.
The two workers are each pulling up with a force of 225 N, and since they are pulling in the same direction, we can add their forces to get a total pulling force of 2 * 225 N = 450 N.
The slab of concrete applies a gravitational force of 400 N in the opposite (downward) direction.
To find the net force, we subtract the gravitational force from the pulling force: 450 N - 400 N = 50 N.
The net force is 50 N, and because it is positive, it means the net force is in the same direction as the pulling force. Therefore, the slab of concrete will move in the direction in which the workers are pulling, which is upward.
A spring scale shows a net force of 0.8 N acting on a 1.5-kg mass. What happens to the acceleration of the object if the net force is decreased to 0.2 N?
To determine the effect on the acceleration, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
According to the given information, the net force acting on the 1.5-kg mass is initially 0.8 N. Therefore, we can calculate the initial acceleration using Newton's second law:
Acceleration = Net Force / Mass = 0.8 N / 1.5 kg ≈ 0.53 m/s²
If the net force is decreased to 0.2 N, we can calculate the new acceleration using the same formula:
New Acceleration = New Net Force / Mass = 0.2 N / 1.5 kg ≈ 0.13 m/s²
Therefore, if the net force is decreased to 0.2 N, the acceleration of the object will also decrease to approximately 0.13 m/s².