Let the sample space be Upper S equals StartSet 1 comma 2 comma 3 comma 4 comma 5 comma 6 EndSet
.
Suppose the outcomes are equally likely. Compute the probability of the event Eequals
"an
odd
number."
There are 6 outcomes in the sample space, and out of those, there are 3 odd numbers (1, 3, and 5).
Since the outcomes are equally likely, the probability of an odd number is given by the number of favorable outcomes (3) divided by the total number of outcomes (6).
Therefore, the probability of the event E, "an odd number," is 3/6 or 1/2.
To compute the probability of the event E, which is "an odd number", we need to find the number of outcomes that satisfy this event and divide it by the total number of possible outcomes.
In this case, the sample space S is {1, 2, 3, 4, 5, 6}.
Let's find the number of outcomes that satisfy the event E, which is "an odd number". The odd numbers in the sample space are {1, 3, 5}, so the number of outcomes that satisfy E is 3.
Now, let's find the total number of possible outcomes. In this case, the total number of elements in the sample space is 6.
Therefore, the probability of the event E, P(E), is given by:
P(E) = (Number of outcomes that satisfy E) / (Total number of possible outcomes)
= 3 / 6
= 1 / 2
= 0.5
So, the probability of the event E, which is "an odd number", is 0.5 or 50%.
To compute the probability of the event E, which is "an odd number," we need to determine the number of outcomes in the sample space that satisfy this event and divide it by the total number of outcomes in the sample space.
Given that the sample space S is {1, 2, 3, 4, 5, 6}, we need to identify the outcomes in S that are odd numbers. In this case, the odd numbers in S are {1, 3, 5}.
Therefore, the number of outcomes in S that satisfy the event E is 3.
The total number of outcomes in the sample space is 6, as there are six elements in S.
Now, we can calculate the probability of the event E by dividing the number of outcomes satisfying E by the total number of outcomes in the sample space:
P(E) = (Number of outcomes satisfying E) / (Total number of outcomes in the sample space)
= 3 / 6
= 1/2
= 0.5
So, the probability of the event E, "an odd number," is 0.5 or 50%.