Suppose y varies directly with x, and y=10 when x=-3
What direct variation equation relates x and y
What is the value of y when x=-1
If y varies directly with x, we can write the equation as y = kx, where k is the constant of variation.
Given that y = 10 when x = -3, we can substitute these values in the equation to find the value of k:
10 = k(-3)
Dividing both sides by -3:
k = -10/3
Therefore, the direct variation equation relating x and y is y = (-10/3)x.
To find the value of y when x = -1, we can substitute x = -1 into the equation:
y = (-10/3)(-1)
y = 10/3
The value of y when x = -1 is 10/3 or approximately 3.333.
To find the direct variation equation that relates x and y, we can use the formula:
y = kx
where k is the constant of variation.
Given that y = 10 when x = -3, we can substitute these values into the equation to solve for k:
10 = k(-3)
Dividing both sides by -3:
k = 10 / -3
k = -10/3
Therefore, the direct variation equation relating x and y is:
y = (-10/3)x
To find the value of y when x = -1, we can substitute x = -1 into the equation:
y = (-10/3)(-1)
y = 10/3
Thus, when x = -1, the value of y is 10/3.
To find the direct variation equation relating x and y, we can use the following formula:
y = kx
where k is the constant of variation.
Given that y = 10 when x = -3, we can substitute these values into the equation to solve for k:
10 = k * (-3)
To solve for k, divide both sides of the equation by -3:
k = 10 / -3
Therefore, the constant of variation is k = -10/3.
Now that we have the equation, we can find the value of y when x = -1. We can substitute this value into the equation:
y = (-10/3) * (-1)
y = 10/3
Therefore, when x = -1, y = 10/3.