It’s opening day at an amusement park. There are 132 people in line before it officially opens. If the ratio of adults to kids waiting to get in is 5:6, how many kids are waiting in line?
Let's represent the number of adults as 5x and the number of kids as 6x.
The total number of people waiting in line is 5x+6x=11x=132
Multiplying both sides by 1/11 we get x=12
The number of kids in line is 6(12)=<<6*12=72>>72. Answer: \boxed{72}.
The total ratio of adults to kids is 5:6. To find the number of kids waiting in line, we need to divide the total number of people in line by the sum of the ratio's parts, which is 5 + 6 = 11.
Let's calculate the number of kids waiting in line:
Number of kids = (number of kids' parts / total parts) * total number of people in line
Number of kids = (6 / 11) * 132
Simplifying:
Number of kids = 0.545 * 132
Number of kids = 71.94
Since we cannot have a fraction of a kid, we round the number of kids waiting in line to the nearest whole number.
Number of kids waiting in line = 72.
To answer this question, we need to find the number of kids waiting in line.
The given ratio of adults to kids is 5:6. This means that for every group of 5 adults in line, there are 6 kids in line.
Let's calculate the number of adults and kids in line separately:
Step 1: Calculate the total number of parts in the ratio.
5 (parts for adults) + 6 (parts for kids) = 11 (total parts)
Step 2: Divide the total number of people in line (132) by the total number of parts (11) to find the value of one part.
132 (total people) ÷ 11 (total parts) = 12 (value of one part)
Step 3: Multiply the value of one part (12) by the number of parts for kids (6) to find the number of kids in line.
12 (value of one part) * 6 (parts for kids) = 72 kids
Therefore, there are 72 kids waiting in line.