After a three-tenths increase of her current hourly wage, a woman receives a new hourly wage of $20.18. How much was her hourly wage before the increase?
Let her hourly wage before the increase be x.
The increase of three-tenths is equal to 3/10 * x = 0.3x.
The new hourly wage is x + 0.3x = $20.18.
Combining like terms, we get 1.3x = $20.18.
Dividing both sides by 1.3, we get x = $15.52.
Therefore, her hourly wage before the increase was $15.52. Answer: \boxed{15.52}.
To find out the woman's hourly wage before the increase, you can use the formula:
Previous hourly wage = New hourly wage / (1 + Increase rate)
First, convert the three-tenth increase to decimal form: 3/10 = 0.3
Next, plug in the given values into the formula:
Previous hourly wage = $20.18 / (1 + 0.3)
Calculating the fraction in the denominator:
Previous hourly wage = $20.18 / 1.3
Finally, divide $20.18 by 1.3 to find the previous hourly wage:
Previous hourly wage ≈ $15.52
Therefore, the woman's hourly wage before the increase was approximately $15.52.
To find out the woman's hourly wage before the increase, we need to work backwards. Let's call her previous hourly wage "x".
We know that she received a three-tenths increase. In other words, her new wage is 1.3 times her previous wage:
New wage = 1.3 * x = $20.18
To find the value of x, we can divide the new wage by 1.3:
x = $20.18 / 1.3
Using a calculator, we can evaluate this expression to find the value of x:
x ≈ $15.52
Therefore, the woman's hourly wage before the increase was approximately $15.52.