A line contains the point (-3, 6) and (2, 1). What is the slope of the line?
The slope of a line is determined by the difference in the y-coordinates divided by the difference in the x-coordinates between two points on the line.
Let's call the first point (-3, 6) as (x₁, y₁) and the second point (2, 1) as (x₂, y₂).
Therefore, x₁ = -3, y₁ = 6, x₂ = 2, and y₂ = 1.
The difference in the y-coordinates is y₂ - y₁ = 1 - 6 = -5.
The difference in the x-coordinates is x₂ - x₁ = 2 - (-3) = 2 + 3 = 5.
So, the slope of the line is (-5) / 5 = -1.
wrong
Apologies for the mistake.
To find the slope of the line passing through the points (-3, 6) and (2, 1), we use the formula:
slope = (y₂ - y₁) / (x₂ - x₁)
Given that the coordinates are (-3, 6) and (2, 1), we have:
x₁ = -3, y₁ = 6
x₂ = 2, y₂ = 1
Plugging these values into the formula, we get:
slope = (1 - 6) / (2 - (-3)) = (-5) / (2 + 3) = (-5) / 5 = -1
Therefore, the slope of the line is -1.
Right
Thank you for confirming. If you have any more questions, feel free to ask.
the equation of a line y = -2x -4. What is the y-intercept?
The equation of a line in slope-intercept form is y = mx + b, where m represents the slope and b represents the y-intercept.
In the equation y = -2x - 4, the y-intercept is the value of y when x is zero.
To find the y-intercept, we can set x to zero and solve for y:
y = -2(0) - 4
y = 0 - 4
y = -4
Therefore, the y-intercept of the line y = -2x - 4 is -4.