F (x)=3ײ 4×-2,find f(2× 3)
To find f(2x^3), we can substitute the value of 2x^3 into the function F(x).
F(x) = 3x^2 + 4x - 2
f(2x^3) = 3(2x^3)^2 + 4(2x^3) - 2
Simplifying further:
f(2x^3) = 3 * 4x^6 + 4 * 2x^3 - 2
f(2x^3) = 12x^6 + 8x^3 - 2
Therefore, f(2x^3) = 12x^6 + 8x^3 - 2.
To find f(2x+3), we need to substitute 2x+3 in place of x in the given function f(x)=3x²+4x-2.
Replacing x with 2x+3, we get:
f(2x+3) = 3(2x+3)² + 4(2x+3) - 2
Expanding and simplifying the expression:
f(2x+3) = 3(4x²+12x+9) + 8x+12 - 2
f(2x+3) = 12x²+36x+27 + 8x+10
Combining like terms:
f(2x+3) = 12x²+44x+37
Therefore, f(2x+3) = 12x²+44x+37.
To find \(f(2x+3)\), we replace the variable \(x\) in the given function \(f(x) = 3x^2 + 4x - 2\) with \(2x+3\).
Let's substitute \(2x+3\) for \(x\) in the function:
\(f(2x+3) = 3(2x+3)^2 + 4(2x+3) - 2\)
To simplify, we need to expand the terms:
\(f(2x+3) = 3(4x^2 + 12x + 9) + 4(2x+3) - 2\)
Multiplying each term within the bracket by 3:
\(f(2x+3) = 12x^2 + 36x + 27 + 8x + 12 - 2\)
Combining like terms:
\(f(2x+3) = 12x^2 + 44x + 37\)
Therefore, \(f(2x+3) = 12x^2 + 44x + 37\)