What is the formula of a compound that contains 13.9% calcium 63.9% tungsten and oxygen?
The chemical formula of a compound that contains 13.9% calcium, 63.9% tungsten, and oxygen is CaWO4.
This compound is called calcium tungstate.
To determine the formula of a compound containing calcium, tungsten, and oxygen, we need to find the ratio of the elements present in the compound.
First, let's assume 100g of the compound. This means that we have 13.9g of calcium and 63.9g of tungsten.
Next, we need to convert the masses of calcium and tungsten into moles. To do this, we divide the mass of each element by their respective molar masses.
The molar mass of calcium (Ca) is 40.08 g/mol, so the number of moles of calcium is 13.9g / 40.08 g/mol = 0.347 mol.
The molar mass of tungsten (W) is 183.84 g/mol, so the number of moles of tungsten is 63.9g / 183.84 g/mol = 0.347 mol.
Now we need to find the molar ratio between calcium and oxygen. The molar ratio of oxygen is usually a multiple of whole numbers, so we need to multiply both calcium and tungsten by an appropriate factor to make their mole ratios whole numbers.
In this case, it appears that calcium and tungsten have the same number of moles, 0.347. This suggests that the formula of the compound may be CaWO4.
In summary, the formula of the compound that contains 13.9% calcium, 63.9% tungsten, and oxygen is most likely CaWO4.
To determine the formula of a compound, we need to use the concept of percent composition. The percent composition of a compound is the percentage by mass of each element present in the compound.
Given that the compound contains 13.9% calcium, 63.9% tungsten, and the rest is oxygen, we can assume that the total mass of the compound is 100 grams.
To find the mass of each element, we'll assume that we have 100 grams of the compound.
Mass of calcium = 13.9 grams (13.9% of 100 grams).
Mass of tungsten = 63.9 grams (63.9% of 100 grams).
Mass of oxygen = 100 grams - (Mass of calcium + Mass of tungsten).
Now we need to convert the mass of each element to moles. We'll use the molar mass of each element to do this.
The molar mass of calcium (Ca) is 40.08 g/mol.
The molar mass of tungsten (W) is 183.84 g/mol.
The molar mass of oxygen (O) is 16.00 g/mol.
To find the number of moles:
Number of moles of calcium = mass of calcium / molar mass of calcium.
Number of moles of tungsten = mass of tungsten / molar mass of tungsten.
Number of moles of oxygen = mass of oxygen / molar mass of oxygen.
Once we have the moles of each element, we need to find the mole ratio.
Divide the number of moles of each element by the smallest number of moles to find the mole ratio for each element.
Finally, we can determine the empirical formula using the mole ratio.
The empirical formula is the simplest ratio of the elements present in the compound. It gives the relative number of atoms of each element in the compound.
For example, if the mole ratio of calcium is 1, tungsten is 2, and oxygen is 3, the empirical formula would be CaWO3.
Please use this method to calculate the empirical formula for the given compound.