Use the properties of operations to add 9(k+13)+10(12k−1) .(1 point) Responses 14k+13 14 k plus 13 1912k−23 19 Start Fraction 1 over 2 End Fraction k minus Start Fraction 2 over 3 End Fraction 14k−7 14 k minus 7 14k−23
To add 9(k+13) + 10(12k-1), we will first distribute the 9 and 10 to their respective terms inside the parentheses.
9(k+13) = 9k + 9(13)
10(12k-1) = 10(12k) + 10(-1)
This gives us:
9k + 117 + 120k - 10
Now, we can combine like terms:
9k + 120k + 117 - 10
Combining the coefficients, we have:
(9k + 120k) + (117 - 10)
129k + 107
Therefore, the answer is 129k + 107.
To add 9(k + 13) + 10(12k - 1), we can use the distributive property to simplify the expression:
9(k + 13) + 10(12k - 1)
= 9k + 9(13) + 10(12k) - 10(1)
= 9k + 117 + 120k - 10
= (9k + 120k) + (117 - 10)
= 129k + 107
To simplify the given expression, 9(k+13) + 10(12k-1), we need to follow the properties of operations that include the distributive property.
First, let's apply the distributive property to each term:
9 * k + 9 * 13 + 10 * 12k - 10 * 1
Simplifying each term:
9k + 117 + 120k - 10
Now, let's combine like terms:
(9k + 120k) + (117 - 10)
This simplifies to:
129k + 107
So, the simplified expression is 129k + 107.