A bird is flying at an average altitude of 10 meters above the ground. After 3 seconds, it settles on a branch that is 3 meters above the ground. Interpret the quotient to describe the rate of change in the birds altitude. Give ur answer to the nearest hundredth and remember that the bird is descending.
The quotient that best represents the range of change in the birds altitude is ______ meters/second
To find the rate of change in the bird's altitude, we can calculate the difference in altitude divided by the difference in time.
Initial altitude (after 3 seconds): 10 meters
Final altitude (on the branch): 3 meters
Difference in altitude: 10 - 3 = 7 meters
Difference in time: 3 seconds
Rate of change in altitude = (Difference in altitude) / (Difference in time)
Rate of change in altitude = 7 meters / 3 seconds ≈ 2.33 meters/second
Therefore, the quotient that best represents the rate of change in the bird's altitude is approximately 2.33 meters/second.
To find the rate of change in the bird's altitude, we need to calculate the difference in altitude divided by the time it takes to descend.
The bird's initial altitude is 10 meters above the ground, and after 3 seconds, it settles on a branch that is 3 meters above the ground. Therefore, the difference in altitude is 10 - 3 = 7 meters.
The time it takes for the bird to descend is 3 seconds.
So, the rate of change in the bird's altitude is 7 meters / 3 seconds.
Calculating this quotient, we get 2.33 meters/second (rounded to the nearest hundredth).
Therefore, the quotient that best represents the range of change in the bird's altitude is approximately 2.33 meters/second.
To find the quotient that best represents the rate of change in the bird's altitude, we need to calculate the change in altitude divided by the change in time.
The change in altitude is the difference between the bird's initial altitude and its final altitude. In this case, the initial altitude is 10 meters above the ground, and the final altitude is 3 meters above the ground. So, the change in altitude is 10 - 3 = 7 meters.
The change in time is the difference between the initial time and the final time. In this case, the initial time is 0 seconds (when the bird starts flying) and the final time is 3 seconds (when the bird lands on the branch). So, the change in time is 3 - 0 = 3 seconds.
To find the quotient, we divide the change in altitude (7 meters) by the change in time (3 seconds):
Quotient = Change in altitude / Change in time
= 7 meters / 3 seconds
≈ 2.33 meters/second
Therefore, the quotient that best represents the rate of change in the bird's altitude is approximately 2.33 meters/second.