Use (x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2 to generate a polynomial identity when x equals 5 and y equals 3.
Substituting the values x=5 and y=3 into the equation (x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2, we have:
(5^2+3^2)^2=(5^2-3^2)^2+(2*5*3)^2
(25+9)^2=(25-9)^2+(30)^2
(34)^2=(16)^2+(30)^2
Simplifying the equation further, we get:
1156 = 256 + 900
Hence, the polynomial identity when x=5 and y=3 is 1156 = 1156.
To generate a polynomial identity when x equals 5 and y equals 3, we substitute these values into the equation (x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2.
Substituting x = 5 and y = 3, we have:
(5^2 + 3^2)^2 = (5^2 - 3^2)^2 + (2*5*3)^2
Simplifying,
(25 + 9)^2 = (25 - 9)^2 + (30)^2
(34)^2 = (16)^2 + (30)^2
1156 = 256 + 900
1156 = 1156
Therefore, when x equals 5 and y equals 3, the polynomial identity (x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2 holds true.
To generate a polynomial identity using the equation (x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2 when x equals 5 and y equals 3, we substitute the given values into the equation:
(5^2 + 3^2)^2 = (5^2 - 3^2)^2 + (2*5*3)^2
Simplifying further:
(25 + 9)^2 = (25 - 9)^2 + (30)^2
(34)^2 = (16)^2 + (30)^2
1156 = 256 + 900
1156 = 1156
Therefore, when x equals 5 and y equals 3, the equation (x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2 holds true.