add 2√8 + 3√8
Apologies for the mistake. Let's solve it correctly.
To add √31 + √31, we combine the coefficients of the radicals:
1√31 + 1√31 = (1 + 1)√31 = 2√31
Therefore, √31 + √31 = 2√31.
To add 2√8 and 3√8, first, observe that both terms have the same radical (√8). We can combine the coefficients of the radicals and keep the same radical.
The coefficients are 2 and 3. We add them together to get 2 + 3 = 5.
Therefore, 2√8 + 3√8 = 5√8.
add √31 + √31
To add √31 + √31, we need to combine like terms. Since both terms have the same radical (√31), we can simply add their coefficients together.
The coefficients are both 1. Therefore, 1√31 + 1√31 = 1 + 1 = 2.
So, √31 + √31 = 2.
thats not right
subtract √29 - √29
To subtract √29 - √29, we combine like terms. Since both terms have the same radical (√29), we can simply subtract their coefficients.
The coefficients are both 1. Therefore, 1√29 - 1√29 = 1 - 1 = 0.
So, √29 - √29 = 0.
Add 22−−√3 + 322−−√ + 22−−√ .(
To add 22−−√3 + 322−−√ + 22−−√, we first simplify the radicals:
22−−√3 can be simplified by multiplying the coefficient 2 by the square root (√) of 3: 2√3.
322−−√ remains as it is, since the square root of 22 is not a perfect square.
22−−√ also remains as it is, since the square root of 2 is not a perfect square.
Now we can add the terms with the same radicals:
2√3 + 322−−√ + 22−−√ = 2√3 + 322−−√ + 22−−√
There are no like terms to combine, so this is the final answer: 2√3 + 322−−√ + 22−−√.