Use the equation and the table to answer the question.

FeCIz + 3H20 -> Fe(OH)з + 3HCI
.all 5G8 284
Mark as Complete
Element
Fe
CI
H
O
Mass of an Atom (amu)
56
35
1
16
Iron chloride and water react according to the equation shown.
The table shows the atomic masses of the elements involved in the reaction. What is the total mass of the reactants?
(1 point)

O 161 amu
O 108 amu
O 215 amu
О 179 amu

The total mass of the reactants can be determined by adding the atomic masses of all the atoms involved in the reaction.

For FeCl2, we have:
1 Iron atom (Fe) with a mass of 56 amu
2 Chlorine atoms (2 x Cl) with a mass of 35 amu each, resulting in a total mass of 70 amu.

For H2O, we have:
2 Hydrogen atoms (2 x H) with a mass of 1 amu each, resulting in a total mass of 2 amu.
1 Oxygen atom (O) with a mass of 16 amu.

Adding the masses together:
Total mass of FeCl2 + H2O = (56 amu + 70 amu) + (2 amu + 16 amu) = 126 amu + 18 amu = 144 amu.

Therefore, the total mass of the reactants is 144 amu.

Your wrong

I apologize for the incorrect response. Let me recalculate the total mass of the reactants.

For FeCl2, we have:
1 Iron atom (Fe) with a mass of 56 amu
2 Chlorine atoms (2 x Cl) with a mass of 35 amu each, resulting in a total mass of 70 amu.

For H2O, we have:
3 Hydrogen atoms (3 x H) with a mass of 1 amu each, resulting in a total mass of 3 amu.
1 Oxygen atom (O) with a mass of 16 amu.

Adding the masses together:
Total mass of FeCl2 + H2O = (56 amu + 70 amu) + (3 amu + 16 amu) = 126 amu + 19 amu = 145 amu.

Therefore, the total mass of the reactants is 145 amu. Thank you for pointing out the mistake, and I apologize for any confusion caused.

The option is

• 161 amu
• 108 amu
• 215 amu
• 179 amu

Apologies for the previous incorrect answer. Let's calculate the total mass of the reactants correctly.

For FeCl2, we have:
1 Iron atom (Fe) with a mass of 56 amu
2 Chlorine atoms (2 x Cl) with a mass of 35 amu each, resulting in a total mass of 70 amu.

For H2O, we have:
3 Hydrogen atoms (3 x H) with a mass of 1 amu each, resulting in a total mass of 3 amu.
1 Oxygen atom (O) with a mass of 16 amu.

Adding the masses together:
Total mass of FeCl2 + H2O = (56 amu + 70 amu) + (3 amu + 16 amu) = 126 amu + 19 amu = 145 amu.

Therefore, the correct option for the total mass of the reactants is 145 amu.

FeCIz + 3H20 -> Fe(OH)з + 3HCI

Iron chloride and water react according to the equation shown.
The table shows the atomic masses of the elements involved in the reaction. What is the total mass of the reactants?
(1 point)

O 161 amu
O 108 amu
O 215 amu
О 179 amu

To calculate the total mass of the reactants, we need to consider the atomic masses of the elements involved in the reaction.

For FeCl2, we have:
1 Iron atom (Fe) with a mass of 56 amu
2 Chlorine atoms (2 x Cl) with a mass of 35 amu each, resulting in a total mass of 70 amu.

For H2O, we have:
3 Hydrogen atoms (3 x H) with a mass of 1 amu each, resulting in a total mass of 3 amu.
1 Oxygen atom (O) with a mass of 16 amu.

To find the total mass of the reactants, we add the masses together:
Total mass of FeCl2 + H2O = (56 amu + 70 amu) + (3 amu + 16 amu) = 126 amu + 19 amu = 145 amu.

Therefore, the correct answer is O 145 amu.

FeCI^3 + 3H^2o -> Fe(OH)з + 3HCI

Apologies for the previous incorrect answers. Let's recalculate the total mass of the reactants correctly.

For FeCl3, we have:
1 Iron atom (Fe) with a mass of 56 amu
3 Chlorine atoms (3 x Cl) with a mass of 35 amu each, resulting in a total mass of 105 amu.

For H2O, we have:
6 Hydrogen atoms (6 x H) with a mass of 1 amu each, resulting in a total mass of 6 amu.
3 Oxygen atoms (3 x O) with a mass of 16 amu each, resulting in a total mass of 48 amu.

Adding the masses together:
Total mass of FeCl3 + H2O = (56 amu + 105 amu) + (6 amu + 48 amu) = 161 amu + 54 amu = 215 amu.

Therefore, the correct option for the total mass of the reactants is O 215 amu.

In a chemical reaction, two molecules with a total mass of 76 amu react to form a single molecule. What is the mass of the molecule that is formed?

(1 point)
O 76 amu
O 228 amu
O 38 amu
O 152 amu