Sodium reacts with chlorine to form the compound sodium chloride, or salt. The chemical formula below shows how the two elements combine into a compound.
2Na + GIz -> 2NaCI
If the total mass of the reactants is 58.44 amu, what will be the total mass of the products?
(1 point)
a 60 amu
b 58.44 amu
c 116.88 amu
d 29.22amu
The chemical formula shows that 2 moles of sodium (Na) react with 1 mole of chlorine (Cl) to form 2 moles of sodium chloride (NaCl).
To find the total mass of the products, we need to determine the molar mass of sodium chloride (NaCl).
The molar mass of sodium (Na) is 22.99 g/mol, and the molar mass of chlorine (Cl) is 35.45 g/mol.
Therefore, the molar mass of sodium chloride (NaCl) is:
2 (molar mass of Na) + 1 (molar mass of Cl) = (2)(22.99) + 35.45 = 45.98 + 35.45 = 81.43 g/mol.
Since the total mass of the reactants is given as 58.44 amu, and the molar mass of the products is 81.43 g/mol, we can determine the total mass of the products using the following calculation:
(total mass of reactants) x (molar mass of products) / (molar mass of reactants)
= 58.44 amu x (81.43 g/mol) / (58.44 g/mol)
= 81.43 amu
Therefore, the total mass of the products will be 81.43 amu.
The correct answer is: a) 81.43 amu.
that is not right
To determine the total mass of the products, we need to find the molar masses of the reactants (sodium and chlorine) and the products (sodium chloride).
The molar mass of sodium (Na) is 22.99 g/mol, and the molar mass of chlorine (Cl) is 35.45 g/mol. To find the molar mass of sodium chloride (NaCl), we need to sum the molar masses of sodium and chlorine.
Molar mass of NaCl = Molar mass of Na + Molar mass of Cl
= 22.99 g/mol + 35.45 g/mol
= 58.44 g/mol
Now, since the total mass of the reactants is given as 58.44 amu, the total mass of the products (NaCl) will also be 58.44 amu.
Therefore, the correct answer is b) 58.44 amu.
To find the total mass of the products, we need to calculate the molar mass of sodium chloride and then multiply it by the number of moles of sodium chloride formed.
The molar mass of sodium chloride (NaCl) is calculated by adding the atomic weights of sodium (Na) and chlorine (Cl). The atomic weight of sodium (Na) is approximately 22.99 amu, and the atomic weight of chlorine (Cl) is approximately 35.45 amu.
So, the molar mass of NaCl is 22.99 amu + 35.45 amu = 58.44 amu.
Now, from the balanced chemical equation, we can see that 2 moles of sodium react to form 2 moles of sodium chloride. Therefore, the number of moles of sodium chloride formed is also 2.
To find the total mass of the products, we multiply the molar mass of sodium chloride (58.44 amu) by the number of moles of sodium chloride (2 moles):
Total mass of products = molar mass of NaCl × number of moles of NaCl
Total mass of products = 58.44 amu × 2
Total mass of products = 116.88 amu
Therefore, the correct answer is c) 116.88 amu. The total mass of the products is 116.88 amu.