a point is translated on the coordinate plane from (-4,1) to (4,2). journey writes the function g(y) =y+k to describe the translations. what is the value of k?

To find the value of k, we need to determine the translation in the y-direction, or the change in the y-coordinate of the point.

From (-4, 1) to (4, 2), the y-coordinate increased by 1. Therefore, the value of k is 1.

Thus, the value of k is 1.

Triangle PQR is reflected over a vertical line of reflection to create triangle P'Q'R' . What are the coordinates of point R' ?

If triangle PQR is reflected over a vertical line of reflection, it means that the x-coordinate of each point is negated.

Let's say the coordinates of point R are (x, y). After the reflection over the vertical line, the x-coordinate gets negated, so the x-coordinate of R' will be -x. The y-coordinate remains the same.

Therefore, the coordinates of point R' will be (-x, y).

Triangle PQR is reflected over a vertical line of reflection to create triangle P'Q'R' . What are the coordinates of point R' ?

(-3,1)
(-2,7)
(1,-3)
(11,1)

If triangle PQR is reflected over a vertical line of reflection, the x-coordinate of each point will be negated.

If the coordinates of point R are (x, y), the coordinates of point R' will be (-x, y).

Among the given options, neither (-3, 1), (-2, 7), nor (11, 1) have negated x-coordinates. The only option with a negated x-coordinate is (1, -3).

Therefore, the coordinates of point R' are (1, -3).

For triangle FUN, x= -1. what are the coordinates for F' after a reflection?

F'(5.-5)
F'(3,5)
F'(-1,4)
F'(-5,-5)

Since triangle FUN is reflected over the line x = -1, it means that all the x-coordinates of the points will be the negation of their original values.

Among the given options, F'(-1, 4) has the negated x-coordinate. Therefore, the coordinates for F' after the reflection are (-1, 4).

The coordinate point Q(0,10) is reflected over the y-axis. identify the x- and y-coordinates of its image, Q'

When a point is reflected over the y-axis, its x-coordinate is negated while the y-coordinate remains the same.

The original coordinates of point Q are (0, 10). After reflecting over the y-axis, the x-coordinate will be negated, resulting in (-0, 10). However, we typically do not include the negative sign in front of zero, so the x-coordinate of the image, Q', is simply 0.

Therefore, the x-coordinate of point Q' is 0, while the y-coordinate remains 10.

Hence, the coordinates of point Q' are (0, 10).

a double reflection of a preimage across perpendicular lines produce the same result as a