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Of the cars in a used-car lot, 25 are the color gray. 13 of the gray cars are electrically powered vehicles. What fraction of the cars on the lot are both gray and electrically powered? Leave your answer in simplified fraction form.

To find the fraction of cars that are both gray and electrically powered, we need to divide the number of gray and electric cars by the total number of cars on the lot.

The number of gray cars is 25, and the number of gray and electric cars is 13.

Therefore, the fraction of cars that are both gray and electrically powered is 13/25.

Of the cars in a used-car lot, 2/5 are the color gray. 1/3 of the gray cars are electrically powered vehicles. What fraction of the cars on the lot are both gray and electrically powered? Leave your answer in simplified fraction form.

To find the fraction of cars that are both gray and electrically powered, we need to multiply the fractions representing the proportion of gray cars and the proportion of electrically powered cars among the gray cars.

The fraction of cars that are gray is 2/5, and the fraction of electrically powered cars among the gray cars is 1/3.

Therefore, the fraction of cars that are both gray and electrically powered is (2/5) * (1/3) = 2/15.

Lake Profondo has a depth of 84 feet. Lake Segundo is 5/6 as deep. What is the elevation at the bottom of Lake Segundo? (Remember, the elevation is below sea level. Account for this in your answer.)

If Lake Profondo has a depth of 84 feet, and Lake Segundo is 5/6 as deep, we can find the depth of Lake Segundo by multiplying its depth by 5/6.

Depth of Lake Segundo = (5/6) * 84 feet = 70 feet.

The elevation at the bottom of Lake Segundo would be 70 feet below sea level.

Divide −72 by −4. Then divide the quotient by −9. What is the final quotient?

When dividing -72 by -4, we get a quotient of 18.

So, -72 divided by -4 equals 18.

Now, when we divide the quotient 18 by -9, we get a final quotient of -2.

Thus, the final quotient is -2.

What is the quotient of 100÷(−10)÷5?

Responses

−2
negative 2

−200
negative 200

2
2

−50