Given the formula for the volume of a box, V=lwh, which equation best represents the remaining units when justifying your rearrangement to solve for the width?
The equation that best represents the remaining units when rearranging the formula V=lwh to solve for the width is:
w = V / (lh)
This equation shows that the width is equal to the volume divided by the product of the length and height.
To solve for the width (w) in the equation V = lwh, we need to rearrange the equation. Currently, the width is being multiplied by the length (l) and the height (h). We can isolate the width (w) by dividing both sides of the equation by both the length (l) and the height (h).
The equation can be rearranged as follows to solve for the width (w):
V / (lh) = w
Therefore, the equation that best represents the remaining units when justifying the rearrangement to solve for the width is:
V / (lh) = w
To solve for the width (w) in the formula for the volume of a box (V = lwh), we need to rearrange the equation. To explain the process of rearranging the equation, let's break it down step by step:
1. Start with the original equation: V = lwh
2. To solve for the width (w), we need to isolate it on one side of the equation. To do this, we can divide both sides of the equation by both the length (l) and the height (h):
V / (lh) = (lwh) / (lh)
3. Simplifying the equation, we can cancel out the lh terms on the right-hand side, leaving:
V / (lh) = w
4. We have now isolated the width (w) on one side of the equation. So the rearranged equation that solves for the width is:
w = V / (lh)
Therefore, the correct equation that represents the remaining units when justifying the rearrangement to solve for the width is:
w = V / (lh)