A car sitting at rest begins accelerating at 2.40 m/s? for 15.0 seconds. How far has the car gone?
To find out how far the car has gone, we need to use the equation for distance travelled during constant acceleration:
distance = initial velocity * time + 0.5 * acceleration * time^2
Given:
Initial velocity (u) = 0 m/s (since the car was at rest)
Acceleration (a) = 2.40 m/s^2
Time (t) = 15.0 seconds
Plugging these values into the equation, we get:
distance = 0 * 15.0 + 0.5 * 2.40 * 15.0^2
distance = 0 + 0.5 * 2.40 * 225.0
distance = 0 + 0.5 * 540.0
distance = 270.0 meters
Therefore, the car has gone a distance of 270.0 meters.
To find the distance the car has gone, we can use the equation:
d = (1/2)at^2
Where:
d = distance
a = acceleration
t = time
Given:
a = 2.40 m/s²
t = 15.0 s
Plugging in the values, we have:
d = (1/2)(2.40 m/s²)(15.0 s)^2
Calculating this expression step-by-step:
d = (1/2)(2.40 m/s²)(225.0 s²)
d = (1/2)(540.0 m²/s²)
d = 270.0 m
Therefore, the car has gone 270.0 meters.
To find the distance the car has traveled, we can use the equation of motion:
distance = initial velocity * time + (1/2) * acceleration * time^2
Given:
- Initial velocity (u) = 0 m/s (the car is at rest)
- Acceleration (a) = 2.40 m/s^2
- Time (t) = 15.0 seconds
Plugging these values into the equation, we get:
distance = 0 * 15.0 + (1/2) * 2.40 * (15.0^2)
Calculating the equation:
distance = 0 + 0.5 * 2.40 * 225
distance = 270 meters
Therefore, the car has traveled a distance of 270 meters.