Write the linear equation 3y=6x−18 in slope-intercept form
To write the linear equation 3y = 6x - 18 in slope-intercept form, we need to isolate the y-term and rewrite the equation in the form y = mx + b, where m represents the slope and b represents the y-intercept.
Start by dividing both sides of the equation by 3:
3y/3 = (6x - 18)/3
This simplifies to:
y = 2x - 6
So, the linear equation 3y = 6x - 18 in slope-intercept form is y = 2x - 6.
To write the equation 3y = 6x - 18 in slope-intercept form (y = mx + b), we need to isolate y on one side of the equation.
Given equation: 3y = 6x - 18
First, divide both sides of the equation by 3 to isolate y:
3y/3 = (6x - 18)/3
Simplifying,
y = 2x - 6
So, the linear equation 3y = 6x - 18 in slope-intercept form is y = 2x - 6.